Not hard If you know how (homework) I don't

  • Thread starter Thread starter mushhhy
  • Start date Start date
  • Tags Tags
    Hard Homework
AI Thread Summary
The discussion revolves around a request for help with a physics homework problem involving calculations of acceleration, mass, force, kinetic energy, work, weight, momentum, and impulse. The poster is struggling with specific calculations, particularly in determining the correct values for work and understanding the implications of negative values in kinetic energy. Clarifications are sought on the application of formulas, especially regarding the angle in the work equation, with advice suggesting that if force is applied horizontally, the angle should be zero, making the calculation straightforward. The poster expresses urgency in receiving assistance to complete the assignment and prepare for an upcoming test. Overall, the thread highlights the need for peer support in understanding physics concepts and calculations.
mushhhy
Messages
7
Reaction score
0
Does anyone out there have a few minutes to review a problem I worked out ?

I need to know where I am making errors and how to correct them

If you have a few minuted and are willing to help a fella out please reply ASAP

Here goes The problem states to find the following
1. Acceleration 5. Work
2. mass 6.the weight of three rayovac cells placed on the object
3. Force 7. momentum with and without cells
4. KE 8. Impulse upon collision

Trial 1 weight of object = 985.5 g .986 kg
Xi = 100cm ti = 0
Xf = 38cm tf = 4sec

I need velocity for accelartion v = d/ t = -.62 m/4s = -0.155 m/s

a = v / t = (0.155 m/s) / 4 s = -0.039 m/s^2

mass = w / g = 0.986kg / (9.8 m/s^2) = 0.101kg (why is ans. not in Newtons)

Force F = m x a =0.101kg x (-0.039 m/s^2) = - 2.59 N

KE = (1/2) m x v^2 = (1/2)(0.101kg)(-0.155 m/s)^2 = -0.024 J, (can J be -)

work W = (F cos 0) X = ? I am stuck here, the object is on a level surface I am thinking that (cos 90) is correct am I right ?
PLease any help will be appreciated I am trying to complete assignment and study for test. :eek:
 
Physics news on Phys.org
I see that this post is being viewed but not answered,

Did I do something wrong or is there an error in the post

I could really use a little help with this problem

Is there anyone out there just make a post if you can read me is there anyone at home
 
Okay.What's the text of the problem...?

Daniel.
 
mushhhy said:
work W = (F cos 0) X = ? I am stuck here, the object is on a level surface I am thinking that (cos 90) is correct am I right ?
PLease any help will be appreciated I am trying to complete assignment and study for test.

W=Fdcos(\theta)
if the force is being applied horizontally, then \theta would be zero

Work is force times distance times cos(theta). In this case, if the force is being applied horizontally, then theta=0 so... cos(0)=1 so work would just be W=F*d
 
:cry: Thank you
The problem was an experiment done in class, it is set up as a collision between two cars on a track. one stationary and one propelled by a fan.
Xi = 100cm, Xf = 38cm, ti = 0, tf =4s the rest of the problem is in my first post. If you need any further info let me know I will check back every few minutes. I am trying to figure out some other problems.

Thanks again
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top