Not (null T) is a subspace of V?

159
13
If T is a linear operator L(V,W) then can we say that all the vectors (in the vector space V) that T does not map to the zero vector (in the vector space W) form a subspace call it X?

If a collection of vectors forms a subspace then they must satisfy closure under vector addition and scalar multiplication and there must also exist an additive identity. Taking this into consideration, it is clear that the elements of X are closed under addition (but multiplication not so sure), but its not clear (to me atleast) if W has an additive identity.

Why is X closed?
Suppose the set {x1,x2,...} is a basis for X then the action of T on any linear combination of this set will not lead to a zero vector in W (by linearity of T)

However, if we can never get a zero vector in W by T on X then since T is linear we cannot have the scalar zero multiplying the elements of X since T(0*x)=0 (required for linearity) where x ε X. Hence the additive identity doesnt belong to X?

If this doesnt work can someone suggest an alternative definition for X such that this would work?
My present definition is X = { v ε V : Tv =\=0} .

Thank you :) my motivation here is purely aesthetic i just wanted to write V=(null T)⊕ X

Note: I wasnt able to write "is an element of" so i represented it by epsilon ε
 
159
13
If i define X such that the intersection of X with null T is the zero vector then this definition works this leads to V = null T ⊕ X. But i am still interested in what went wrong with the earlier definition?
 

RUber

Homework Helper
1,687
344
I suppose you simply need to declare that the zero vector is in all three spaces. Adding the zero vector into X should take care of your requirements for X to be a subspace.
 

RUber

Homework Helper
1,687
344
The problem with your earlier definition was just that...it didn't include the zero vector. Every vector space includes the additive identity, and any linear operator acting on the zero vector must return zero, so you can be sure zero was not in X.
 
159
13
Yeah, thank you :)
 

RUber

Homework Helper
1,687
344
Often you see this referred to as the column space of the operator T.
 

HOI

8
2
In general, given subspace U of vector space, V, the set of all vectors that are NOT in U does NOT form a subspace.
 

Related Threads for: Not (null T) is a subspace of V?

  • Last Post
Replies
5
Views
4K
Replies
12
Views
7K
Replies
3
Views
2K
Replies
6
Views
2K
Replies
7
Views
809
Replies
2
Views
733
  • Last Post
Replies
1
Views
5K
Top