- #1
Asphyxiated
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Homework Statement
[tex] \lim_{x \to 1} \frac {\int^{x}_{1} \frac{1}{t} dt} {\int^{x}_{1} \frac {1}{(2t+1)}dt} [/tex]
Homework Equations
The Attempt at a Solution
I am not really sure how I am suppose to approach this problem, I would think that as x approaches 1 the integrals will approach 0 because an integral from n to n is 0. So if that is correct and I am suppose to use l'hopital's rule (since I am still in that section) obviously I am suppose to take the derivatives of those functions but how do I apply the limit after I do that? will it just be:
[tex] \lim_{x \to 1} \frac {\int^{x}_{1} f'(t) dt}{\int^{x}_{1} g'(t) dt} [/tex]
or would the integrals not apply anymore?... i really just don't know, if the integral still applies i basically have the same equation though, as it will end up being 0/0, which is no good.
Supposedly the answer is 3