Nuetralization Reaction involving a weak acid and weak base

AI Thread Summary
The discussion centers on the reaction between acetic acid (CH3OOH) and ammonia (NH3), questioning whether it qualifies as a neutralization reaction involving a weak acid and weak base. It is noted that if "neutralization" is defined by achieving a pH of 7, the resulting ammonium acetate would approximate this pH. However, if equimolar acid/base pairs are the criteria, a reaction with sodium bicarbonate would be more appropriate. Concerns are raised about ammonia being a gas, which could lead to improper neutralization. Additionally, the resulting ammonium ion (NH4+) is recognized as a significant acid, suggesting that the reaction could function as a buffer solution rather than a classic neutralization.
JM_BC
Messages
1
Reaction score
0
CH3OOH (aq) + NH3 (aq) ‹———› NH4+ (aq) + CH3COO- (aq)

Would the above reaction, involving acetic acid and ammonia qualify as a proper neurtalization reaction involving a weak acid and weak base? Or, would a reaction involving acetic acid and sodium bicarbonate be better?

Regards
 
Chemistry news on Phys.org
It depends on what you understand from "neutralization". If you mean pH=7 point for it, then ammonium acetate will almost just give pH=7 level. If you mean equimolar acid/base pair, then the second one will fit better.

Ammonia is okay, but it is a gas and there is a probablity of improper neutralization.

By the way, welcome to the forum.
 
Probably not. The salt formed through such a reaction will contribute to the pH, NH4 is a significant acid.
 
The above could be treated as a buffer solution, right?
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!
Back
Top