Number of atoms reacting with a gas

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The discussion revolves around calculating the number of oxygen atoms reacting with aluminum in the reaction 4Al + 3O2 = 2Al2O3, given 45 dm³ of O2 gas. The initial calculations correctly determine the number of moles of gas using the volume and molar volume at STP, but the mistake occurs in interpreting the number of atoms. Participants clarify that each O2 molecule contains two oxygen atoms, which must be accounted for in the final calculation. The correct approach leads to a much larger number of reacting oxygen atoms than initially stated. Understanding the molecular composition of O2 is crucial for accurate atom counting in chemical reactions.
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Homework Statement


4Al + 3O2 = 2Al2O3
What number of O-atoms will react if 45dm3 of the gas reacts with an excess of Al?
The answer is apparently: 4 atoms

Homework Equations





The Attempt at a Solution


Using the formula n=V/Vn (or the law stating that any gas occupies 22.4dm3 at STP), I found that the number of moles was (225/112) or 2.01. Then I used the formula: n=n*Na (number of moles times Avagadro's Constant) giving me 1.24*1024 atoms. Where did I go wrong please?
 
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The answer is not 4 atoms.

I have no idea what 225/112 means, even if the number of moles seems to correct.

You have 45 L of the gas, there is 22.4 L per mole - how many moles of the gas?

You have correctly converted number of moles of gas to number of molecules, however, you forgot that there is more than one atom per molecule.
 
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