MHB How Many Students Are Not Involved in Any Afternoon Activities?

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In a university with 88 students, 30 students do not participate in any afternoon activities. The participation breakdown includes 33 in activity A, 28 in activity B, and 33 in activity C, with various overlaps among the activities. A Venn diagram is recommended for visualizing the intersections and solving the problems effectively. The answers for the second and third questions are debated, with one participant suggesting 7 for only activity A and another calculating 10 for those in A or B but not C. The discussion emphasizes the utility of both Venn diagrams and algebra of sets for solving such problems.
Yankel
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Hello all,

I am struggling with this relatively simple task.

In a university with 88 students, each student can choose to participate in 3 afternoon activities: activity A, activity B and activity C. Each student can choose to participate in some activities, all or none.

33 students participate in activity A
28 students participate in activity B
33 students participate in activity C
14 students participate in activity A and B
18 students participate in activity A and C
10 students participate in activity B and C
6 students participate in activity A, B and C

1. How many students decided not to participate in any activity ?
2. How many students participate ONLY in activity A ?
3. How many students participate in activity A OR B, but NOT in C ?

I think I did "1" OK, I got that the answer is 30 (am I correct ?).

I solved it using union and intersection, and using the rule of union of 3 sets.

I find it hard to solve "2" and "3".
 
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You are correct for question 1. I find a Venn diagram is an invaluable tool for problems of this sort. Draw 3 intersecting circles to represent the 3 activities, and then work from the inside out, that is, start with the intersection of all 3, then fill in the 3 intersections of the pairs, and finally the 3 parts of each set with no intersection. You will then have all the information you need to easily answer the remaining 2 questions.

Can you proceed?
 
I think I understand what you mean by inside out, I think I can proceed, thank you !

Just for curiosity, isn't it also possible to be done using algebra of sets ?
 
Yankel said:
...
Just for curiosity, isn't it also possible to be done using algebra of sets ?

My inclination is that it is, but this is not an area in which I am very knowledgeable. I just find a Venn diagram to be very straightforward for a problem like this. :D
 
Ok, thanks :)

Just to verify, in "2" and "3", are the answers 7 and 10 ?
 
I agree with 7 for question 2, but for question 3 I have a different answer. I get 10 as the number of students participating only in activity B, but we need to include those that participate only in A AND in A and B (but not C).
 
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