Number of ways that seven toys can be distributed

In summary, the correct way to find the number of ways to give seven different toys to three children, with the youngest receiving three and the others two, is to use the formula C(7,3)*C(4,2) = 210. Another way to approach this problem is to first give the youngest three toys (C(7,3)), and then distribute the remaining four toys equally between the other two children (C(4,2)). Both methods will yield the same result of 210 possible ways.
  • #1
NihalRi
134
12

Homework Statement


Find the number of ways in which seven different toys can be given to three children, if the youngest vis to receive three and the others two.

Homework Equations

The Attempt at a Solution


7 combination 3 × 4 combination 2 × 2 combination 2
= 210
Is this the correct way of doing this question?
 
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  • #2
NihalRi said:

Homework Statement


Find the number of ways in which seven different toys can be given to three children, if the youngest vis to receive three and the others two.

Homework Equations

The Attempt at a Solution


7 combination 3 × 4 combination 2 × 2 combination 2
= 210
Is this the correct way of doing this question?

If you calculate it the other way round, starting with one of the children that gets two toys, do you get the same answer?
 
  • #3
PeroK said:
If you calculate it the other way round, starting with one of the children that gets two toys, do you get the same answer?
Yes still 210, hoping this means it's right?
 
  • #4
NihalRi said:
Yes still 210, hoping this means it's right?

It's a good sign! Yes, it's right!
 
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  • #5
NihalRi said:

Homework Statement


Find the number of ways in which seven different toys can be given to three children, if the youngest vis to receive three and the others two.

Homework Equations

The Attempt at a Solution


7 combination 3 × 4 combination 2 × 2 combination 2
= 210
Is this the correct way of doing this question?

It is OK, but another way (maybe easier?) is: C(7,3) = number of different ways of giving the youngest 3 toys. That leaves 4 toys to be distributed, 2 each to the other two, and the number of different ways of doing that (with the given leftover four toys) is C(4,2). Altogether, the number of ways is C(7,3)*C(4,2) = 210.
 
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1. How many different ways can seven toys be distributed among three children?

There are 35 different ways that seven toys can be distributed among three children. This can be calculated using the formula for combinations, which is nCr = n! / (r!(n-r)!), where n is the total number of toys and r is the number of children. In this case, n = 7 and r = 3, so the calculation would be 7C3 = 7! / (3!(7-3)!) = 35.

2. Is it possible for each child to receive the same number of toys?

No, it is not possible for each child to receive the same number of toys when there are seven toys and three children. This is because 7 cannot be divided evenly by 3. In order for each child to receive the same number of toys, the total number of toys would need to be a multiple of the number of children.

3. Can the toys be distributed in any order?

Yes, the toys can be distributed in any order. This means that if you have three children named A, B, and C, and seven toys labeled 1, 2, 3, 4, 5, 6, and 7, the following distributions would all be considered different: A: 1, 2, 3; B: 4, 5; C: 6, 7 and A: 1, 2, 3; B: 6; C: 4, 5, 7.

4. How many ways are there to distribute seven toys among seven children?

There is only one way to distribute seven toys among seven children. This is because each child will receive one toy, and there are no other possible combinations.

5. What is the minimum and maximum number of toys that each child can receive?

The minimum number of toys that each child can receive is zero, meaning that some children may not receive any toys. The maximum number of toys that each child can receive is seven, meaning that each child could potentially receive all seven toys.

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