wel
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The nonlinear oscillator y'' + f(y)=0 is equivalent to the
Simple harmonic motion:
y'= -z,
z'= f(y)
the modified Symplectic Euler equation are
y'=-z+\frac {1}{2} hf(y)
y'=f(y)+\frac {1}{2} hf_y z
and deduce that the coresponding approximate solution lie on the family of curves
2F(y)-hf(y)y+z^2=constant
where F_y= f(y).
ans =>
for the solution of the system lie on the family of curves, i was thinking
\frac{d}{dt}[2F(y)-hf(y)y+z^2]= y \frac{dy}{dt} + z \frac{dz}{dt}
=y(-z+\frac{1}{2} hf(y)) +z(f(y)- \frac{1}{2} h f_y z)
but I can not do anything after that to get my answer constant.
can any genius people please help me
Simple harmonic motion:
y'= -z,
z'= f(y)
the modified Symplectic Euler equation are
y'=-z+\frac {1}{2} hf(y)
y'=f(y)+\frac {1}{2} hf_y z
and deduce that the coresponding approximate solution lie on the family of curves
2F(y)-hf(y)y+z^2=constant
where F_y= f(y).
ans =>
for the solution of the system lie on the family of curves, i was thinking
\frac{d}{dt}[2F(y)-hf(y)y+z^2]= y \frac{dy}{dt} + z \frac{dz}{dt}
=y(-z+\frac{1}{2} hf(y)) +z(f(y)- \frac{1}{2} h f_y z)
but I can not do anything after that to get my answer constant.
can any genius people please help me