Object falling down and object falling up

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Object A falls at a terminal velocity of 20 m/s from 1000 m, while object B is launched downward at 125 m/s. Calculations indicate that object A takes approximately 12.385 seconds to reach the ground, while object B reaches the ground in about 6.396 seconds. The discussion highlights the need to determine the height at which both objects will collide, requiring the formulation of equations based on their respective distances and times. It is clarified that an object falling at terminal velocity does not accelerate further. The conclusion emphasizes that object B cannot reach a height of 1000 m before impacting the ground.
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Homework Statement


A object A falling down at terminal velocity of 20 m/s, at 1000m above the ground another object B fly at it at an initial velocity of 125 m/s.

a) how much time before object A hits object B?


Homework Equations



X = Xo + Vo(t) + 1/2AT^2

G = 9.8 m/s^2

The Attempt at a Solution



using the equation i found it takes object A 12.385 second to fall down from 1000
m while object B 6.321 second to reach 1000 m

but I am not sure how i can find out when they will hit each other.
 
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Suppose they meet at a height x from the ground. Then the distance moved by A is 1000 - x and distance move by B is x. A is moving with uniform velocity where as B is moving with the acceleration. When they meet, they must have taken the same time. So write two equations and solve for x.
 
Does an object falling at terminal velocity accelerate? Why not?

So, you time for object A is incorrect.

Object B will not reach a height of 1000 m.

An object launched downward at 125 m/s from a 1000 m altitude, will reach the ground in 6.396 s, ignoring air resistance.
 
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