Object subjected to constant force, determine the force

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An object with a mass of 3 kg is subjected to a constant force in the x-y plane, starting from rest and displacing to 2i + 4j at t=2 seconds. To determine the force, the equation of motion is applied, specifically Rf = Ri + Vi(t) + 1/2(a)T^2, noting that initial velocity is zero. The acceleration can be calculated by analyzing displacement in both x and y directions, leading to the conclusion that force equals mass times acceleration (F=ma). The discussions emphasize the importance of correctly applying kinematic equations and understanding the relationship between acceleration and force. The final answer for the force will be expressed in unit vector form.
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Homework Statement


An object of Mass 3 in the x-y plane is subjected to a constant force F (in addition to its weight). The object starts from rest at x=0 y=0 and t=0. At t=2 the object's displacement is 2i+4j. Determine F.


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The Attempt at a Solution

Where do I begin? I know you have the position it moved so would I use work. Or do I need to find the acceleration and try and Find F that way?
 
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If you know the general solution to Newton's second law of motion, then you would just need to plug-in the numbers to find the answer. The key here is to note that the force is constant.
 


So would I use an Integral to figure it out since it is a constant force? or would I use F=MA.
 


student 1 said:
So would I use an Integral to figure it out since it is a constant force?
Essentially, that's what you will do, but the solution to that is something you are probably already familiar with. It's an equation of motion.
 


Equation of motion is confusing me? Would I say it traveled the magnitude of the disposition vector or that it only traveled 2 m in x direction?
 


student 1 said:
Equation of motion is confusing me? Would I say it traveled the magnitude of the disposition vector or that it only traveled 2 m in x direction?

Find the equation that relates displacement, initial velocity and time lapsed and use it to find the acceleration, in both the x and y directions. And you must be knowing how acceleration relates to force.
 


ok so you use Rf=Ri+Vi(t)+1/2(a)T^2 in both direction and since it started at rest you have no initial velocity. so u basically multiply the I and J by 2 to get your acceleration and the F would be your mass times acceleration. Right?
 


student 1 said:
ok so you use Rf=Ri+Vi(t)+1/2(a)T^2 in both direction and since it started at rest you have no initial velocity.
That's right. That equation would look better (accurate, actually) if you substitute tf - ti for t.

so u basically multiply the I and J by 2 to get your acceleration

Huh?

and the F would be your mass times acceleration. Right?
Right.
 


Alright, I messed up algebraically what I'm saying is since the rest of the equation is o+o+1/2A(Tf-Ti)^2, So you would have 2-0 for the T square that would give you 4. 1/2(A)4 would give you 2a so you would divide that and find each acceleration. Will your final answer be in unit vector form for the force?
 
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