Oblique impact on ground of a ping ping ball

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When a ping pong ball strikes the ground obliquely without spinning, the angle of incidence does not equal the angle of reflection. Upon impact, the ball deforms, transferring momentum to the ground and creating a reaction force that leads to upward acceleration. However, energy loss occurs due to sound and deformation, resulting in a smaller upward acceleration than the initial downward deceleration. Consequently, the ball's velocity after impact is less than before impact. Additionally, friction causes the ball to start spinning after contact, similar to the effect observed in airplane wheels during touchdown.
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When a ping pong ball strikes the ground obliquely without spinning, the angle of incidence is not equal to that of reflection, am I correct? Here is my thoughts: Assume the ground is smooth and negligible air resistance. When the ball touches the ground, it starts to deform, delivering its momentum to the ground(is it right to say so??) . After a split second, it retains its shape due to its elasticity, applying a force to the ground. A reaction force appears which causes an upward acceleration to the ball. However, due to energy loss as sound, the loss in elastic pe is less than the loss in gravitational pe before the ball reaches the ground. Therefore the upward acceleration is smaller in magnitude than the deceleration during impact. The resultant velocity of the ball after impact thus does not equal that before impact.
Please correct my mistakes, if any.
 
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That's one reason.
And other - dominant and having reverse effect - is that ball after such collision starts spinning. Point on the bottom of the ball was moving with some horizontal speed, the same, as whole ball. After touch, in the very short time, friction stops it. In effect the ball starts to spin.

You may see the same effect much more spactacularily: watch the wheels of landing airplane at the moment of touchdown.
 
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