Ocean Depth at 7.07s Echo Time - 1.22311 km

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The discussion revolves around calculating ocean depth using echo time from a geological survey ship. An echo time of 7.07 seconds indicates a one-way travel time of 3.535 seconds. The initial calculation used the speed of sound in air, yielding a depth of 1.22311 kilometers. However, the correct speed of sound in seawater, which varies with salinity, pressure, and temperature, should be used for accurate results. Additionally, variations in salinity affect sound propagation, complicating underwater acoustics and submarine detection.
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A geological survey ship mapping the floor of the ocean sends sound pulses down from the surface and measures the time taken for the echo to return. How deep is the ocean at a point where the echo time (down and back) is 7.07 s? The temperature of the seawater is 25°C. Find the answer in km

7.07 / 2 = 3.535 seconds to get from surface to ocean bedrock.
v = 331 + .6*25 = 346 m/s

3.535 * 346 = 1223.11 m ==> 1 223.11 meters = 1.22311 kilometers

This is wrong according to the online homework I'm doing?
 
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Perhaps you need the speed of sound in sea water instead of air?
 
Your math is correct as far as I can see. However... the equation you are using for the speed of sound is for air. It is different in water. The actual equation is very complex and dependent on salinity and pressure as well as temperture. You obviously were not given salinity and pressure varies with depth so maybe I am making this too complex. Ideas anyone?

Just for interest: Salinity changes in the oceans causes the sound to bend and reflect in an unpredictable manner. This allows subs to hide beneath various layers making sub hunting a very difficult problem.
 
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