Is f(x) = x^2 on [-5,10] an even function?

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The function f(x) = x^2 is defined on the interval [-5,10]. For a function to be classified as even, it must satisfy the condition f(-x) = f(x) for all x in its domain. Since the domain [-5,10] is not symmetric around zero, f(x) cannot be considered an even function. Therefore, it is incorrect to claim that f(x) = x^2 is even on this interval. The discussion emphasizes the importance of domain symmetry in determining the evenness of a function.
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f(x) is an even function if f(-x) = f(x) for any x in the domain of f.
Now I say that f(x) = x^2 is defined on [-5,10]. Can I say f(x) is an even function?
 
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No, you can't.
An odd or even function must be defined on a symmetric domain.
But [-5,10] is not symmetric.
 
Is f(8)= f(-8)?
 
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