On differentiation and indices in field theory

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SUMMARY

The discussion centers on the manipulation of indices in field theory, specifically regarding the transformation of indices in the context of the Lagrangian density. The rule stated is that if the index is lowered on the denominator, it corresponds to a raised index. An example from Peskin & Schroeder's "Introduction to Quantum Field Theory" illustrates this with the conserved current derived from the Lagrangian $$\mathcal{L} = \frac{1}{2}(\partial_\mu\phi)^2$$ and the differentiation process leading to $$\frac{\partial\mathcal{L}}{\partial(\partial_\mu\phi)} = \partial_\mu\phi$$. The discussion confirms that the expression $$\partial_\mu\phi$$ must be interpreted as $$\partial_\mu\phi = (\partial_\mu\phi)(\partial^\mu\phi)$$ to maintain Lorentz invariance.

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  • Understanding of index notation in tensor calculus
  • Familiarity with Lagrangian mechanics in quantum field theory
  • Knowledge of Lorentz invariance principles
  • Basic concepts of conserved currents in field theory
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Students and researchers in theoretical physics, particularly those focusing on quantum field theory and the mathematical foundations of field theory. This discussion is beneficial for anyone looking to deepen their understanding of index manipulation and Lorentz invariance.

Nauj Onerom
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I'm self-studying field theory and trying to solidify my understanding of index manipulations. So I've been told that there is a general rule: " If the index is lowered on the 'denominator' then it's a raised index". My question is whether this is just a rule or something that can make sense mathematically. For example (taken from ch. 2 of P&S Intro to QFT), for a transformation $$\phi\rightarrow\phi + \alpha,$$ of the Lagrangian $$\mathcal{L} = \frac{1}{2}(\partial_\mu\phi)^2 ,$$ we get a conserved current

$$ j^{\mu} = \frac{\partial \mathcal{L}}{\partial(\partial_\mu \phi)}.$$

If we differentiate normally we get $$\frac{\partial\mathcal{L}}{\partial(\partial_\mu\phi)} = \partial_\mu\phi,$$ but this has a lowered index. How do I see that this is supposed to be raised? ?
 
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What is meant by ##(\partial_\mu \phi)^2## is typically ##(\partial_\mu\phi)(\partial^\mu\phi)##. Otherwise the term would not be Lorentz invariant.
 
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Orodruin said:
What is meant by ##(\partial_\mu \phi)^2## is typically ##(\partial_\mu\phi)(\partial^\mu\phi)##. Otherwise the term would not be Lorentz invariant.
Very clear now, thanks !
 

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