- #1
mohabitar
- 140
- 0
h(x,y)=x/(y+1)
I'm not understanding why this function is NOT one to one? How do I quickly see if this function is one to one? I am not getting the overall concept of this..
I'm not understanding why this function is NOT one to one? How do I quickly see if this function is one to one? I am not getting the overall concept of this..