Op Amp Voltage Expression & Simplification Homework Solution

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Discussion Overview

The discussion revolves around developing and simplifying an expression for the output voltage (Vo) of an operational amplifier (op-amp) based on a given circuit. Participants explore the implications of treating the op-amp as ideal versus non-ideal, focusing on the mathematical expressions and potential errors in reasoning.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents an initial attempt at deriving Vo using the equation Vo=A(Vp-Vn) and expresses uncertainty about the simplification process.
  • Another participant suggests that for an ideal op-amp, the two 6V sources can be ignored, but notes that real-world considerations like common mode rejection ratio may apply.
  • There is a question about whether Vo would simply equal Vs for an ideal op-amp, with some participants indicating potential sign errors in the equations presented.
  • One participant proposes an alternative interpretation of the equation, suggesting that Vo could be expressed differently, which may resolve the sign error concern.
  • A participant mentions that the circuit shown operates in open-loop mode, implying that the output would be infinite times Vs for an ideal op-amp, and critiques the circuit's suitability.
  • Another participant raises the point that the circuit might be better described as a comparator rather than an amplifier, indicating a shift in perspective on the circuit's function.
  • Concerns are expressed about output spikes when the input transitions through Vs=0V, highlighting potential practical issues with the circuit design.

Areas of Agreement / Disagreement

Participants express varying views on the correct interpretation of the equations and the implications of treating the op-amp as ideal versus non-ideal. There is no consensus on the final expression for Vo, and multiple competing interpretations of the circuit's behavior are present.

Contextual Notes

Participants note potential sign errors in the equations and the need for additional context regarding the non-ideal aspects of the op-amp in question. The discussion reflects uncertainty about the correct approach to simplifying the expression and the implications of the circuit design.

Pepjag
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Homework Statement



I have to use the basic equivalent model of an op-amp to develop an expression for Vo from the given op-amp. I also have to simplify the expression by treating the given op-amp as an ideal op-amp.

Homework Equations



Vo=A(Vp-Vn)
Vo=G*Vs

The Attempt at a Solution



Vp=6v
Vn=6-Vs

Vo = A(6-6-Vs) = -A*Vs. Am I on the right track? I don't even know how to start on the other half of the problem. I've only had half a lecture on op-amps.
 

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Looks right so far.

For an ideal op-amp you can essentially ignore the two 6v sources. For a real world op-amp you might have to check out the common mode rejection ratio.
 
So for an ideal op-amp, would Vo just end up being Vs?
 
Pepjag said:
So for an ideal op-amp, would Vo just end up being Vs?

I think you have a couple small sign errors in your equations, but you are on the right track.

The 6V source and Vs look to add going into the - opamp input, but you have written that equation as a subtraction.

And then When you calculate Vo, you do not account for the fact that Vs is going into the - opamp input. Your answer is almost correct, you just need to fix those two sign errors.
 
Unless, by this equation:

Vo = A(6-6-Vs) = -A*Vs

you mean Vo = A[6 - (6+Vs)] = -A*Vs

If so, then you don't have a sign error.
 
The attached circuit shows an op amp in open-loop operation.

That means that, ignoring offsets, output = AVs.

It also means the output is infinty times Vs if the op amp is ideal.

Very unsuitable circuit!
 
Pepjag said:
So for an ideal op-amp, would Vo just end up being Vs?

For an ideal opamp the output would be -A*Vs where A => ∞ as others have said.

Is there more text to go with the diagram? The title of the thread says "Non-ideal Op Amp voltage". To answer your question fully we would need to know what was Non-ideal about it.
 
rude man said:
Very unsuitable circuit!

well you might start to call it a comparator instead of an amplifier.
 
as long as you don't mind some spikes on the output as the input transitions through Vs=0V.
 

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