Operational Amplifier Circuit for Adding AC & DC Signals

Click For Summary

Discussion Overview

The discussion revolves around designing a circuit that adds an AC signal of 25mV to a variable DC signal (0 to 5V) for application to a diode, specifically for measuring the capacitance-voltage (C-V) characteristics of a reverse-biased diode. The conversation includes various methods for superimposing these signals using operational amplifiers and other components.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Experimental/applied

Main Points Raised

  • Some participants suggest using an operational amplifier to create a unity-gain summer to combine the AC and DC signals.
  • Others propose using bias resistors and an AC coupling capacitor to form a high pass filter, emphasizing the need to select appropriate values.
  • One participant mentions simply connecting the AC source to the inverting input and the DC source to the non-inverting input of the op-amp, adjusting their gains accordingly.
  • Another participant doubts the necessity of a summer, suggesting coupling the AC through a capacitor and connecting it with a resistor from the DC supply.
  • Some participants discuss the use of wide-band transformers for adding AC to DC, noting the potential impact of inductance and RC time-constant considerations.
  • There is a clarification that the experiment is not a varactor experiment, but rather involves measuring the C-V characteristics of a standard diode.
  • One participant expresses uncertainty about the nature of the capacitance being measured, questioning if it relates to the diode itself.
  • Another participant indicates that they will use actual devices for the experiment and aims to obtain a graph of capacitance versus reverse voltage.

Areas of Agreement / Disagreement

Participants express various methods for combining AC and DC signals, with no consensus on the best approach. There is also disagreement regarding the classification of the diode in the context of the experiment, with some insisting it is not a varactor while others suggest it may function similarly.

Contextual Notes

Participants mention the importance of output impedance, the selection of component values, and the implications of using different methods for signal combination, but these aspects remain unresolved and contingent on specific circuit designs.

yasef
Messages
12
Reaction score
0
I need a circuit that adds an AC signal with magnitude of 25mV and a variable DC signal between 0 to 5V, and applies it to a diode.
 
Physics news on Phys.org
How to superimpose AC signal With DC signal with operational amplifier?
 
What do you want to do with the "output" of the diode?

An op-amp can have any number of input resistors, each connected to the (-) input. If each Rin is made equal in value to the single feedback resistor, Rf, then the op-amp forms a unity-gain summer (albeit inverting). Is that good enough for your need?
 
yasef said:
How to superimpose AC signal With DC signal with operational amplifier?

Please ask your question in a better way.

What's the input? What's the output?

What do you mean by superimpose?
 
Hi yasef,

This depends on the output impedance of your AC source, but some simple methods are to use bias resistors and an AC coupling coupling capacitor. This can form a high pass filter, so you need to choose appropriate values. You could also use a summing OpAmp.
 
If you just mean you want a DC and AC signal on the output...then dragonpetter's idea will work....

Or just connect your AC source to the "- input" and connect DC source to "+ input". And plan their gains accordingly.
 
For the diode I will measure the C- V characteristic of the diode. Just thank you for your answer and could you tell me if the output signal of the summing amplifier will consist DC and AC coming together so that I can measure Capacitance and voltage simultaneously.
 
This is what İ want to do:İ want to design a circuit to measure C-V curve of a reverse biased diode. Due to the specifications İ should use a circuit that adds an AC signal with magnitude of 25mV and a variable DC signal between 0 to 5V, and applies it to
a diode. Then İ measure AC current through the diode with a lock-in amplifier by using a built in function. Do you have any ideas how İ can do this?
 
  • #10
Thanks for your answers.This is what İ want to do:İ want to design a circuit to measure C-V curve of a reverse biased diode. Due to the specifications İ should use a circuit that adds an AC signal with magnitude of 25mV and a variable DC signal between 0 to 5V, and applies it to
a diode. Then İ measure AC current through the diode with a lock-in amplifier by using a built in function. Do you have any ideas how İ can do this?
 
  • #11
I doubt that a summer is needed. Just couple the AC through a capacitor and join it with a relatively high resistor from your variable DC supply. You'll be measuring a ratio of voltages to allow you to estimate C, will you? This is a varactor experiment?
 
  • #12
I've always used wide-band transformers for this, so-called modem transformers to be specific.
The DC goes through the secondary and the AC is "added" via the primary.
Works quite well as long as you can tolerate the extra inductance in series with the DC.
A capacitor might also work, but you need to watch out for the RC time-constant.
 
  • #13
This is not a varactor experiment. Actully now I had desined a circuit.
I added a circuit that adds AC signal with Magnitude of 25 mV a variable DC signal between 0 to 5 using with op amp, and applied to a diode. I will measure the AC current through the diode with a lock in amplifier. I will use lock in amplifier built in function generator and auxillary output port. From this experimental setup how can I measure C-V current of a reverse biased diode.
 
  • #14
yasef said:
This is not a varactor experiment.
Okay.
can I measure C-V current of a reverse biased diode.
Then what is C, since it's not capacitance?
 
  • #15
Actually I am not very experienced about these things but I think that varactor is a special case. This is just a diode. C come from diode.
 
  • #16
 Okay, so it's an improvised varactor diode. https://www.physicsforums.com/images/icons/icon14.gif

Will you be using actual devices, or is this going to be a computer simulation?

Is this to be a semi-automated demonstration, or is your goal simply to obtain an accurate graph
of C vs. Vrev for a particular diode?
 
Last edited by a moderator:
  • #17
We will use actual device. I am not sure what do you mean about semi outomated demonstration but our signal source for AC and DC is lock in amplifier. At the and I should abtain a graph of C vs V.
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
4K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K