Optical depth using Bremsstahlung emission coefficient

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Homework Help Overview

The discussion revolves around the concept of optical depth in the context of Bremsstrahlung emission coefficients. Participants are exploring the relationship between optical depth and frequency, particularly at the turnover frequency where tau equals one.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss relevant equations and the significance of plotting log intensity against log frequency to understand the behavior of optical depth. There are attempts to manipulate the optical depth equation based on specific conditions, such as substituting values when tau equals one.

Discussion Status

The discussion is active, with participants offering insights and potential approaches to the problem. There is an indication of willingness to engage further, as one participant expresses interest in direct messaging another for additional questions.

Contextual Notes

There is a mention of class explanations regarding the turnover frequency and its implications for optical depth, suggesting that some foundational knowledge may be assumed in the discussion.

Kayla Martin
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Homework Statement
I am a bit confused how to go about this question.
Relevant Equations
See below.
q_LI.jpg

Equations I think may be relevant:

equations.png
 
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My god, something I can actually help with! (I'm an infrequent visitor here who just sponges you guys with my own questions!)
So hopefully in your "class" it was explained how at the turnover frequency that tau=1 (this can be seen better by plotting the log I vs log nu
Putting that (tau=1) into the optical depth equation (last on your pic), and re-arrange the equation for GHz ^ (-2.1), now put that back into the same optical depth equation (in other words you are substituting your result for the GHz ^ (2.1) when the optical depth was 1. You'll see everything cancel leaving just the result the question asks for`. Hope that helps!
 
weak_phys said:
My god, something I can actually help with! (I'm an infrequent visitor here who just sponges you guys with my own questions!)
So hopefully in your "class" it was explained how at the turnover frequency that tau=1 (this can be seen better by plotting the log I vs log nu
Putting that (tau=1) into the optical depth equation (last on your pic), and re-arrange the equation for GHz ^ (-2.1), now put that back into the same optical depth equation (in other words you are substituting your result for the GHz ^ (2.1) when the optical depth was 1. You'll see everything cancel leaving just the result the question asks for`. Hope that helps!
Am I able to direct message you to ask you another question that relates to this part seeing as you seem to know what you're doing?
 
Kayla Martin said:
Am I able to direct message you to ask you another question that relates to this part seeing as you seem to know what you're doing?
Of course, i don't know what time zone you're in but if i go to sleep before i hear from you i'll be sure to check in tomorrow.
 
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