Optical Spectrum Analyzers - Confused on Units

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 2K views
cambridgejohn
Messages
3
Reaction score
0
Hi!

I am new to these, and off the bat am confused by the units.

Manufacturers quote resolution either in units of length, e.g. 0.04 nm, or HZ. For example,

0.04 pm / 5MHz
0.16 pm / 20 MHz
0.8 pm / 100 MHz.

I am thrown by this since I thought frequency was the inverse of wavelength. I get the length part and can understand when I look at a plot of Power vs. Wavelength.

I know I am overlooking something obvious...please help!

Thanks!
John
 
Physics news on Phys.org
The numbers are not frequencies and wavelengths. The are differences between (or errors in the measurement of) in frequencies and wavelengths.

If a frequency f has wavelength [itex]\lambda[/itex], then
a frequency of f + 5 Mhz has a wavelength of approximately [itex]\lambda[/itex] - 0.04pm, and so on
 
Thanks. The error concept part helps. I can understand when a wavelength is being measured a higher resolution helps out, and that one needs to only buy an OSA which will discern a certain wavelength spectra. And I can understand how the difference part makes sense for the wavelength.

What are the units of the proportion between the frequencies and wavelengths measured?
 
ok. it all makes sense now. just needed to run through some numeric examples using the speed of light to get numbers. thanks again for your help.