Xyius
- 501
- 4
Homework Statement
Call the irradiance at the center of the central Fraunhofer diffraction maximum of a single slit I_0 and the irradiance at some other point in the patterm I. Obtain the ratio I/I_0 for some point on the screen that is 3/4 of a wavelength farther from one edge of the slit than the other.
Homework Equations
Irradiance for single slit diffraction
I=I_0sinc^2(β)
β=\frac{1}{2}kbsin\theta
k=\frac{2\pi}{\lambda}
b=slit size
The Attempt at a Solution
Well I know that when beta is equal to zero, the irradiance is at its maximum. But I do not know if this helps me or not. I honestly do not understand the question. 3/4 of a wavelength farther from one edge of the slit than the other? Don't I need the slit length? How can I make use of this information? Why does it say "than the other." What other point?
I really want to understand this problem. If anyone can help me I would much appreciate it!