Optimization - area of rectangle

  • Thread starter look416
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  • #1
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Homework Statement


If the perimeter of a rectangle is fixed in length, show that the area of the rectangle is greatest when it is square


Homework Equations





The Attempt at a Solution


if the perimeter is fixed in length, then 2x + 2y = c
then no idea to continue from there
 

Answers and Replies

  • #2
Dick
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Ok so far. Now you want to maximize x*y, right? Eliminate one of the variables using the perimeter condition and differentiate, etc.
 
  • #3
rock.freak667
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The Attempt at a Solution


if the perimeter is fixed in length, then 2x + 2y = c
then no idea to continue from there
So what is the area A in terms of x and c?
 

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