Optimization - area of rectangle

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SUMMARY

The discussion centers on the mathematical optimization of a rectangle's area given a fixed perimeter. It is established that the area is maximized when the rectangle is a square. The perimeter condition is defined by the equation 2x + 2y = c, where x and y are the rectangle's dimensions. To find the maximum area, one must express the area A as a function of one variable and apply differentiation techniques.

PREREQUISITES
  • Understanding of basic algebra and geometry
  • Knowledge of differentiation and optimization techniques
  • Familiarity with perimeter and area formulas for rectangles
  • Ability to manipulate equations to isolate variables
NEXT STEPS
  • Study the method of Lagrange multipliers for constrained optimization
  • Learn about the properties of quadratic functions and their maxima
  • Explore calculus applications in real-world optimization problems
  • Investigate geometric interpretations of optimization problems
USEFUL FOR

Students studying calculus, mathematicians interested in optimization, educators teaching geometry, and anyone involved in mathematical problem-solving.

look416
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Homework Statement


If the perimeter of a rectangle is fixed in length, show that the area of the rectangle is greatest when it is square


Homework Equations





The Attempt at a Solution


if the perimeter is fixed in length, then 2x + 2y = c
then no idea to continue from there
 
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Ok so far. Now you want to maximize x*y, right? Eliminate one of the variables using the perimeter condition and differentiate, etc.
 


look416 said:

The Attempt at a Solution


if the perimeter is fixed in length, then 2x + 2y = c
then no idea to continue from there

So what is the area A in terms of x and c?
 

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