Optimizing Double Shear Bolt Design for Safe Load Bearing: A Case Study

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SUMMARY

The discussion focuses on optimizing the design of a double shear bolt joint subjected to a tensile load of 40KN. A UTS 1250 class steel bolt with an allowable stress of 1080 MPa is utilized alongside AA2014 alloy lugs with an allowable stress of 380 MPa. Key calculations involve shear failure, tensile failure, and bearing failure, using the equations sigmaS = P/(2*A), sigmaT = P/2*(w-d), and sigmaBR = P/(d*t). The suggested approach includes testing a bolt diameter of 20 mm to evaluate load capacity and adjusting based on critical failure modes.

PREREQUISITES
  • Understanding of tensile and shear stress calculations
  • Familiarity with materials properties, specifically UTS 1250 class steel and AA2014 alloy
  • Knowledge of failure modes in mechanical design, including shear and bearing failure
  • Basic proficiency in structural analysis and design principles
NEXT STEPS
  • Research the effects of different bolt diameters on load capacity in double shear joints
  • Explore advanced failure analysis techniques for mechanical joints
  • Learn about the design and application of bolted connections in structural engineering
  • Investigate the properties and applications of AA2014 alloy in load-bearing structures
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Mechanical engineers, structural designers, and students involved in bolt design and optimization for load-bearing applications.

dilipdboss
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1. Homework Statement
A tensile load of 40KN is applied on a double shear joint. Design a bolt that holds the members safely without any kind of failure. A UTS 1250 class steel [allowable stress = 1080 MPa, Ultimate strength = 1250 MPa] bolt is used and the members (lugs) are made of AA2014 alloy [allowable stress=380 MPa, Ultimate strength = 420 MPa].

2. Homework Equations
shear failure: sigmaS = P/(2*A)
tensile failure: sigmaT = P/2*(w-d)
bearing failure: sigmaBR = P/(d*t)


thanx for the help.
 
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One way of doing a 'design' like this is to try something. Try, say diameter = 20 mm and see what loads it can carry in double shear and bearing. decide which of these is critical. Compare that with the requirements of the question, and adjust accordingly.
 

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