Optimizing Polymer Coating Thickness for Reflectivity at 500 nm Wavelength?

AI Thread Summary
To optimize polymer coating thickness for reflectivity at a 500 nm wavelength, the refractive indices of the polymer (n=1.30) and the base (n=1.50) are crucial. The minimum thickness of the coating must be calculated to achieve destructive interference, which minimizes reflection. The relevant equations for calculating the thickness involve the wavelength in the medium and the phase shift upon reflection. The discussion references a related thread for additional insights on the topic. Understanding these principles is essential for achieving optimal reflectivity in coatings.
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Homework Statement


A polymer coating has a n=1.30 and a base of n=1.50. What is the minimum thickness of the coating to reflect 500 nm least strongly?


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The Attempt at a Solution

 
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