Orbital Hybridisation: How Tetragon in sp3 is Formed

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In sp3 hybridization, the formation of a tetrahedral geometry is explained through the mixing of one s orbital and three p orbitals from carbon, resulting in four equivalent sp3 hybrid orbitals. Each of these orbitals forms a sigma bond with hydrogen atoms in methane (CH4), leading to bonds that are equal in length and strength. The confusion arises from the distinction between sp and ss sigma bonds; however, in the context of methane, all bonds are equivalent due to hybridization. The discussion emphasizes the importance of understanding hybridization concepts to clarify the uniformity of bond characteristics in methane.
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In sp3 hybridisation, how a tetragon is formed? As per book, in ch4 (methane) there are four sigma bond of same length and strength.
But we are having three sp sigma bonds (between s of H and p of C) and one ss sigma bond( between s of H and s of C). Then how can sp and ss sigma bond be of same length and strength?
 
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You don't understand the concept of hybridization. Reread your book.
 

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