- 1,963

- 3

## Main Question or Discussion Point

I was wondering how much stronger potassium chlorate is vs. potassium nitrate in oxidizing power, and how to look up the information for myself next time if possible. Thanks

- Thread starter Mk
- Start date

- 1,963

- 3

I was wondering how much stronger potassium chlorate is vs. potassium nitrate in oxidizing power, and how to look up the information for myself next time if possible. Thanks

GCT

Science Advisor

Homework Helper

- 1,727

- 0

Find the reduction potential for the anions and compare.

- 1,963

- 3

GCT

Science Advisor

Homework Helper

- 1,727

- 0

From what I remember, the more positive the potential, the better the oxidizing agent.

- 1,963

- 3

- 437

- 1

i have some standard electrode values.

OCl[tex]^{-}_{(aq)}[/tex] + H[tex]^{+}_{(aq)}[/tex] + e[tex]^{-}[/tex] [tex]\Leftrightarrow[/tex] [tex]\frac{1}{2}[/tex]Cl[tex]_{2(aq)}[/tex] + 2H[tex]_{2}[/tex]O[tex]_{(l)}[/tex]

emf = + 1.64 V

NO[tex]^{-}_{3(aq)}[/tex] + 3H[tex]^{+}_{(aq)}[/tex] + 2e[tex]^{-}[/tex] [tex]\Leftrightarrow[/tex] HNO[tex]_{2(aq)}[/tex] + H[tex]_{2}[/tex]O[tex]_{(l)}[/tex]

emf = + 0.94 V

therefore, the chlorate(1) is a stronger oxidising agent.

OCl[tex]^{-}_{(aq)}[/tex] + H[tex]^{+}_{(aq)}[/tex] + e[tex]^{-}[/tex] [tex]\Leftrightarrow[/tex] [tex]\frac{1}{2}[/tex]Cl[tex]_{2(aq)}[/tex] + 2H[tex]_{2}[/tex]O[tex]_{(l)}[/tex]

emf = + 1.64 V

NO[tex]^{-}_{3(aq)}[/tex] + 3H[tex]^{+}_{(aq)}[/tex] + 2e[tex]^{-}[/tex] [tex]\Leftrightarrow[/tex] HNO[tex]_{2(aq)}[/tex] + H[tex]_{2}[/tex]O[tex]_{(l)}[/tex]

emf = + 0.94 V

therefore, the chlorate(1) is a stronger oxidising agent.

Last edited:

- 1,899

- 45

Chlorate isi have some standard electrode values.

OCl[tex]^{-}_{(aq)}[/tex] + H[tex]^{+}_{(aq)}[/tex] + e[tex]^{-}[/tex] [tex]\Leftrightarrow[/tex] [tex]\frac{1}{2}[/tex]Cl[tex]_{2(aq)}[/tex] + 2H[tex]_{2}[/tex]O[tex]_{(l)}[/tex]

emf = + 1.64 V

NO[tex]^{-}_{3(aq)}[/tex] + 3H[tex]^{+}_{(aq)}[/tex] + 2e[tex]^{-}[/tex] [tex]\Leftrightarrow[/tex] HNO[tex]_{2(aq)}[/tex] + H[tex]_{2}[/tex]O[tex]_{(l)}[/tex]

emf = + 0.94 V

therefore, the chlorate(1) is a stronger oxidising agent.

[tex]ClO_3^{-}[/tex]

not

[tex]ClO^{-}[/tex]

- 437

- 1

oooops.... yeah it is ClO3-

- 1,963

- 3

Does this mean it is 1.7x stronger?emf = + 1.64 V

emf = + 0.94 V

therefore, the chlorate(1) is a stronger oxidising agent.