P.d. increases in a step up transformer

  • Thread starter Thread starter sachin123
  • Start date Start date
  • Tags Tags
    Transformer
AI Thread Summary
In a step-up transformer, the potential difference (p.d.) increases due to the ratio of the number of turns in the primary and secondary coils, rather than the length or thickness of the wire. The voltage increase is directly proportional to the number of turns in the secondary coil, which interacts with the magnetic flux generated by the primary coil. The physical properties of the wire, such as length and diameter, do not influence the voltage; instead, factors like flux density and the primary voltage source play a crucial role. Energy conservation is maintained as the increase in voltage results in a decrease in current, keeping power consistent, minus any losses. Understanding these principles clarifies how the transformer operates without relying on formulas.
sachin123
Messages
117
Reaction score
0
just tell me how the p.d. increases in a step up transformer.
(Please don't use formulas for this.)
if we take a conductor of same length and thickness as the 1st one for the secondary coil,
the voltage doesn't increase.
but why does it,if we increase the length.
I mean,how can that affect it?
(Please don't use formulas for this,because i want to see how the formula is derived than the other way round)

and how does it satisfy the law of energy conservation?
Thank You.
 
Physics news on Phys.org


Remember that, as the potential difference increases, the current decreases.
Thus the power remains the same(minus loses in the transformation)
 


again:

if we take a conductor of same length and thickness as the 1st one for the secondary coil,
the voltage doesn't increase.
but why does it,if we increase the length.
I mean,how can that affect it?
(Please don't use formulas for this,because i want to see how the formula is derived than the other way round)
Please tell me how(physically)the length of Secondary Coil affects emf??!??
 


sachin123 said:
again:

if we take a conductor of same length and thickness as the 1st one for the secondary coil,
the voltage doesn't increase.
but why does it,if we increase the length.
I mean,how can that affect it?
(Please don't use formulas for this,because i want to see how the formula is derived than the other way round)
Please tell me how(physically)the length of Secondary Coil affects emf??!??

Please apply simple proportionality rather formulas.
Please tell me how(physically)the length of Secondary Coil affects emf??!??
 


The length and wire diameter don't determine the votlage. The number of turns do.
The ratio of turns is equal to the ratio of the voltages.
 


The length of the secondary winding does not determine secondary emf. Rather, the flux density and secondary number of turns does. The flux density is determined by the primary voltage source, the frequency, the core area, and the primary no. of turns. This flux then couples the secondary winding. The secondary no. of turns (encirclements of the flux) and the magnitude of the flux density, determines the secondary emf.

Does this help?

Claude
 
Back
Top