- #1
Astr
- 14
- 0
Im New on this forum, so i hope this is the right place to ask this question. I've tried to solve the problem of finding how many hands are in a poker game with exactly one pair, this way:
I can choose the first card from 52 ways. for the second card I can choose it from 3 ways (to match the pair). For the third card I can choose it from 48 possibilities (for ensure I´ve got no trios in the hand). For the fourth and fifth i can choose them in 44 and 40 different ways, respectively. And because order is not important I must divide for 5! (ways of permuting 5 cards). My (wrong) answer is:
(52x3x48x44x40)/5!=109 824
This is a tenth of the correct answer. Please can you tell what's wrong in the procedure. (English isn't my first language, sorry if I've got some mistakes)
I can choose the first card from 52 ways. for the second card I can choose it from 3 ways (to match the pair). For the third card I can choose it from 48 possibilities (for ensure I´ve got no trios in the hand). For the fourth and fifth i can choose them in 44 and 40 different ways, respectively. And because order is not important I must divide for 5! (ways of permuting 5 cards). My (wrong) answer is:
(52x3x48x44x40)/5!=109 824
This is a tenth of the correct answer. Please can you tell what's wrong in the procedure. (English isn't my first language, sorry if I've got some mistakes)