Parallel and Series circuits and current

AI Thread Summary
The discussion focuses on understanding the behavior of bulbs in parallel and series circuits, specifically regarding brightness and current flow. Bulb A is brighter than bulbs B and C because B and C are in parallel, increasing the current through A. Adding bulb D increases the overall current in the circuit, making bulb A brighter, while bulb B's brightness remains unchanged since its current does not vary. The current through the bulbs and battery is analyzed, revealing that the addition of parallel components does not affect the voltage across existing parallel bulbs. The conversation highlights the importance of voltage drop considerations in circuit analysis.
motyapa
Messages
4
Reaction score
0

Homework Statement



2 different questions that I'm using to test my understanding of the physics concepts rather than the math:

1)
How does the brightness of bulb A compare to that of bulb C?
Hry6Jg6.png


After D is added how does the brightness of bulb A change?
Does the brightness of B change?
Does the current through the battery change?
BApySao.png


2)
qCk4QhQ.png

What is the current through 1, 2, 3?
What is the current through C, D, E?

Homework Equations



Less math more conceptual, so no equations to use (plus we haven't learned any equations for circuits yet)

The Attempt at a Solution


[/B]
so for 1a I said that bulb A is brighter than bulb B/C because B & C are in parallel with each other, it increases the current through bulb A.

1b I said bulb A becomes brighter, because the addition of bulb D increases the current throughout the whole circuit. Bulb B does not change brightness because the current through its portion does not change, and the current through the battery increases since the overall current through the whole circuit increased.

For 2 I said the current through 1 is 60, equal to the bulb. For 2 I said it's 30, since 30 goes through B, which means 30 will go through C, so 30 reaches the battery equal to the bulb. For 3 I said it's 120, because D and E both have 60 mA since they're in parallel, so the total is 120.

Does my reasoning of these concepts seem good or am I off on something?
 
Physics news on Phys.org
All good, except how the addition of D affects B in 1. Think about the voltage drop across A.
 
  • Like
Likes motyapa
I used this website to try and help me to reach my answer: http://epb.apogee.net/foe/fcspp.asp

it seems like adding more in parallel shouldn't change how bright the other parallel ones are? I'm confused why B should change.
 
Last edited by a moderator:
motyapa said:
I used this website to try and help me to reach my answer: http://epb.apogee.net/foe/fcspp.asp

it seems like adding more in parallel shouldn't change how bright the other parallel ones are? I'm confused why B should change.
You are assuming the voltage across B does not change.
 
Last edited by a moderator:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top