unhip_crayon said:Homework Statement
Two oppositely charged parallel plates, 13.0 cm apart, have a uniform electric
field between them. Vb − Va = +25.0 V. An electron with a mass of
9.11 × 10−31 kg and a charge of −1.60 × 10−19 C is released from rest at plate a.
Calculate the speed of the electron when it reaches plate b.
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a b
The Attempt at a Solution
E=V/d = 25/.13 = 192.3J
I also need you need to find accel. but I am not sure how.
please help, thanks
The speed of an electron reaching Plate B in parallel plates can be calculated using the formula v = E*d/m, where v is the speed, E is the electric field strength, d is the distance between the plates, and m is the mass of the electron.
The electric field strength between parallel plates can be calculated using the formula E = V/d, where E is the electric field strength, V is the voltage between the plates, and d is the distance between the plates.
The distance between the plates has a direct effect on the speed of the electron. As the distance increases, the speed of the electron decreases, and vice versa.
No, the speed of an electron in a vacuum cannot exceed the speed of light, which is approximately 3 x 10^8 meters per second.
Other factors that can affect the speed of the electron reaching Plate B include the voltage between the plates, the material of the plates, and external forces such as magnetic fields.