Parallel transport on flat space

In summary: When parallel transporting a vector along a straight line on flat space, does the connection (when calculating the covariant derivative) always equal zero? Do things change at all when using an arbitrary connection, rather than Christoffel symbols?Yes, in a coordinate-dependent system the connection will always be zero. However, the expression of the connection can vary depending on the coordinate system used.
  • #1
steve1763
13
0
When parallel transporting a vector along a straight line on flat space, does the connection (when calculating the covariant derivative) always equal zero? Do things change at all when using an arbitrary connection, rather than Christoffel symbols?
 
Physics news on Phys.org
  • #2
steve1763 said:
When parallel transporting a vector along a straight line on flat space, does the connection (when calculating the covariant derivative) always equal zero? Do things change at all when using an arbitrary connection, rather than Christoffel symbols?
The connection determines whether space is flat or not.
 
  • Like
Likes steve1763
  • #3
The connection matrix will be the identity in this case. Standard metric with standard Pythagorean theorem.
 
  • Like
Likes PhDeezNutz and steve1763
  • #4
The connection matrix will be the identity in this case. Standard metric with standard Pythagorean theorem.
 
  • Like
Likes PhDeezNutz and steve1763
  • #5
steve1763 said:
When parallel transporting a vector along a straight line on flat space, does the connection (when calculating the covariant derivative) always equal zero? Do things change at all when using an arbitrary connection, rather than Christoffel symbols?

No, whether the connection is zero depends on the coordinates. For example, in flat space, cartesian coordinates have zero connection, but spherical coordinates have a nonzero connection.
 
  • Like
Likes PhDeezNutz, ChinleShale, Klystron and 3 others
  • #6
WWGD said:
The connection matrix will be the identity in this case. Standard metric with standard Pythagorean theorem.
Apologies, I was referring to the metric in general, the Euclidean metric tensor:
content://media/external/file/11536
 
  • Like
Likes PhDeezNutz and steve1763
  • #7
As I understand it an affine connection is a smoothly varying choice of a covariant derivative at each point of the manifold. This does not depend on coordinates, However its expression varies from one set of coordinates to another.

The covariant derivative of a vector field with respect to a vector in flat Euclidean space is just the directional derivative of the vector field along a curve fitting the vector.

A general covariant derivative is analogous to a directional derivative. This analogy can be expressed formally by the way a vector acts on a vector field. Using the mathematical notation ##∇_{X_{p}}Y## for the covariant derivative of the vector field ##Y## with respect to the tangent vector ##X_{p}## at the point ##p##,the formal properties are

1) ##∇_{X_{p}}(aY+bZ)= a∇_{X_{p}}Y+b∇_{X_{p}}Z## for constants ##a## and ##b##
2) ##∇_{aX_{p}+bZ_{p}}Y = a∇_{X_{p}}Y+b∇_{Z_{p}}Y##
3) ##∇_{X_{p}}fY = df(X_{p})Y + f∇_{X_{p}}Y## for an arbitrary function ##f##. This is called the Leibniz rule

Notice that this definition does not depend on a choice of coordinates. Interestingly these is also no use of a metric tensor so curvature is defined even when there are no ideas of length and angle.
 
  • Like
Likes steve1763
  • #8
ChinleShale said:
Notice that this definition does not depend on a choice of coordinates. Interestingly these is also no use of a metric tensor so curvature is defined even when there are no ideas of length and angle.
You do, however, need at least a topology on the manifold in the first place.
 
  • #9
PeroK said:
You do, however, need at least a topology on the manifold in the first place.
But the manifold has topology.
 
  • #10
ChinleShale said:
As I understand it an affine connection is a smoothly varying choice of a covariant derivative at each point of the manifold. This does not depend on coordinates, However its expression varies from one set of coordinates to another.

The covariant derivative of a vector field with respect to a vector in flat Euclidean space is just the directional derivative of the vector field along a curve fitting the vector.

A general covariant derivative is analogous to a directional derivative. This analogy can be expressed formally by the way a vector acts on a vector field. Using the mathematical notation ##∇_{X_{p}}Y## for the covariant derivative of the vector field ##Y## with respect to the tangent vector ##X_{p}## at the point ##p##,the formal properties are

1) ##∇_{X_{p}}(aY+bZ)= a∇_{X_{p}}Y+b∇_{X_{p}}Z## for constants ##a## and ##b##
2) ##∇_{aX_{p}+bZ_{p}}Y = a∇_{X_{p}}Y+b∇_{Z_{p}}Y##
3) ##∇_{X_{p}}fY = df(X_{p})Y + f∇_{X_{p}}Y## for an arbitrary function ##f##. This is called the Leibniz rule

Notice that this definition does not depend on a choice of coordinates. Interestingly these is also no use of a metric tensor so curvature is defined even when there are no ideas of length and angle.

But the original post asked specifically about Christoffel symbols. I don't think you can make sense of those without a choice of coordinates. You certainly can't say, in a coordinate-independent way, that they are zero or nonzero.
 
  • Like
Likes PeroK
  • #11
stevendaryl said:
But the original post asked specifically about Christoffel symbols. I don't think you can make sense of those without a choice of coordinates. You certainly can't say, in a coordinate-independent way, that they are zero or nonzero.
Point well taken.

I had trouble parsing the language, particularly the words "does the connection always equal zero" when parallel translating. It seemed from the language that there might some confusion about what a connection is. From other posts I thought it important to point out that connections are not coordinate dependent but that their expressions in different coordinate systems are different. This could have been a disconnect in my understanding of the language for instance when you wrote in post #5 that the connection is zero in some coordinate systems but not in others.

Also @PeroK 's point in post #2 that the connection determines the curvature states that the correct test of flatness is that the curvature tensor is identically zero. This is a coordinate free statement. I thought it important to underscore this by describing the affine connection in axiomatic terms rather than in terms of local coordinates.

The OP asked about more general connections not using Christoffel symbols. One way to think about this might be to look at affine connections on other vector bundles than the tangent bundle. In those cases there are no Christoffel symbols. Still curvature is well defined and a connection is flat if the curvature tensor is identically zero. A vector field in the bundle is parallel along a curve on the manifold its its covariant derivative is zero. All of the formal structure is the same.
 
Last edited:
  • #12
PeroK said:
You do, however, need at least a topology on the manifold in the first place.
You need a smooth differentiable structure not just a topology.
 

FAQ: Parallel transport on flat space

What is parallel transport on flat space?

Parallel transport on flat space is a concept in differential geometry that describes the movement of a vector or tensor along a path on a flat surface without changing its direction. It is used to study the curvature of space and is an important tool in understanding the behavior of objects in space.

How is parallel transport different from regular transport?

In regular transport, the direction of a vector or tensor may change as it moves along a curved path. In parallel transport, the direction of the vector or tensor remains constant, even as it moves along a curved path. This is because parallel transport takes into account the curvature of space, while regular transport does not.

Why is parallel transport important?

Parallel transport is important because it allows us to study the curvature of space, which is a fundamental concept in physics and mathematics. It helps us understand how objects move and interact in space, and is used in a variety of fields such as general relativity, cosmology, and differential geometry.

What is the relationship between parallel transport and geodesics?

Geodesics are the shortest paths between two points on a curved surface. In parallel transport, the direction of a vector or tensor remains constant as it moves along a geodesic. This means that parallel transport is closely related to geodesics and is often used to study them.

How is parallel transport applied in real-world situations?

Parallel transport has many real-world applications, including in navigation systems, satellite orbits, and computer graphics. It is also used in physics to study the motion of particles in curved space and in engineering to analyze the behavior of structures under stress.

Similar threads

Replies
6
Views
2K
Replies
9
Views
6K
Replies
18
Views
723
Replies
9
Views
4K
Replies
5
Views
3K
Replies
2
Views
3K
Replies
9
Views
3K
Replies
2
Views
2K
Back
Top