Parallel Wires: Force per Unit Length Calculation

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The discussion centers on calculating the force per unit length between two parallel wires carrying the same current. The correct formula for this calculation is F/L = (permeability)/(2*pi*d) * I^2, not 2I as initially stated. The wires are 6.8 cm apart and carry a current of 23.8 A, with the permeability of free space given as 4pi × 10−7 T · m/A. The initial attempt yielded an incorrect result due to the formula error. Correcting this will provide the accurate force per unit length in N/m.
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Homework Statement



Two parallel wires are 6.8 cm apart, and
each carries a current of 23.8 A.
The permeability of free space is 4pi ×
10−7 T · m/A.
If the currents are in the same direction,
find the force per unit length exerted by one
of the wires on the other.
Answer in units of N/m.

Homework Equations



F/L = (permeability)/(2*pi*d) * 2I


The Attempt at a Solution



F/L = (4*pi*10^-7 T*m/A)/(2*pi*0.068m) * 2(23.8 A)
= 0.00014 N/m
 
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Hi Kris1120,

Kris1120 said:

Homework Statement



Two parallel wires are 6.8 cm apart, and
each carries a current of 23.8 A.
The permeability of free space is 4pi ×
10−7 T · m/A.
If the currents are in the same direction,
find the force per unit length exerted by one
of the wires on the other.
Answer in units of N/m.

Homework Equations



F/L = (permeability)/(2*pi*d) * 2I

This equation is not correct. Do you see what it needs to be?
 
I^2 and not 2I!
 
Thanks!
 
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