- #1
Caldus
- 106
- 0
Another question...
If I were given these equations:
x = e^t
y = e^-t
Then I have to find the cartesian product for this parametric curve and then I have to sketch the graph of the curve. So here's the cartesian product I came up with:
Solve for t in y, so:
y = e^-t
ln y = ln e^-t
ln y = -t
t = - ln y
Then plug into the x part:
x = e^-ln y
Is that part correct?
I have no idea how to graph this...
Help appreciated.
If I were given these equations:
x = e^t
y = e^-t
Then I have to find the cartesian product for this parametric curve and then I have to sketch the graph of the curve. So here's the cartesian product I came up with:
Solve for t in y, so:
y = e^-t
ln y = ln e^-t
ln y = -t
t = - ln y
Then plug into the x part:
x = e^-ln y
Is that part correct?
I have no idea how to graph this...
Help appreciated.