Parametric to Cartesian Conversion: Troubleshooting and Identifying Mistakes

  • Thread starter Thread starter autre
  • Start date Start date
  • Tags Tags
    Parameter
autre
Messages
116
Reaction score
0
I have the parametric function x(t) = (1-t^2)/(1+t^2), y(t) = 2t/(1+t^2) and need to eliminate the parameter and find a Cartesian equation.

I've tried to substitute t = tan u, then x(t) = cos(2u) and y(t) = tan(2u). From that I get y = sin(2x)/x. However, when I entered the original parametric function into a grapher, I get an entirely different graph. Where did I go wrong?
 
Physics news on Phys.org
autre said:
I've tried to substitute t = tan u, then x(t) = cos(2u) and y(t) = tan(2u).

I'm not getting that for the y(t) equation. I think it's because you got your identity confused.
\frac{2\tan u}{1 - \tan^2 u} = \tan 2u
(minus in the denominator)

But here we have:
y(t) = \frac{2\tan u}{1 + \tan^2 u} = \frac{2\tan u}{\sec^2 u} = ...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top