Partial derivatives of Gas Law

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SUMMARY

The forum discussion centers on the calculation of partial derivatives related to the Gas Law, specifically demonstrating that the product of the partial derivatives \(\frac{\partial P}{\partial V}\), \(\frac{\partial V}{\partial T}\), and \(\frac{\partial T}{\partial P}\) equals -1. The user, Peter, initially treats pressure (P) as a constant, which leads to confusion since P is inherently a function of temperature (T) and volume (V). The resolution lies in recognizing that during partial differentiation, all variables except the one being differentiated are treated as constants, simplifying the calculation and confirming the exercise's intent.

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peter2108
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In James Stewart's Calculus exercise 82 page 891 asks you to show that:

[itex]\frac{\partial P}{\partial V}\frac{\partial V}{\partial T}\frac{\partial T}{\partial P} = -1[/itex]

I can do this by noting that [itex]V = \frac{nRT}{P}[/itex] so that:

[itex]\frac{\partial V}{\partial T}[/itex] = [itex]\frac{\partial}{\partial T}\left(\frac{nRT}{P}\right)[/itex] = [itex]\frac{nR}{P}[/itex]

and then doing likewise to find the other terms.

But this confuses me because I have treated P as a constant like n and R while it is actually a function of T and V. If I make it a function of T and V I get stuck and anyway the thing gets a lot more complicated than the exercise intends. So how can I just treat P as a constant when I know its not?

Thanks for any help, Peter
 
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When you take a partial derivative of a function of several variables, everything except the variable you are taking the derivative of are considered a constant. All I think the exercise is doing is asking you to take the three partials and multiply them together recognizing that PV in the denominator equals nRT so they cancel leaving -1.
 

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