alex12
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Hello! This is my first post to this excellent forum! I would like some help with this exercise:
u_{xx} (x,y) + u_{yy} (x,y) = 0, with 0 < x < 2 \pi, 0 < y < 4 \pi
u_x (0,y) = 0, \, u_x(2 \pi, y) = 0, \, 0< y < 4 \pi
u(x,0) = a \cos(2x), \, u(x, 4 \pi) = a \cos^3(x), \, 0<x<2\pi
I think that the first step is to set u(x,y) = X(x) Y(y), from which the first equation becomes X''(x) Y(y) + X(x) Y''(y) = 0. And by dividing with X(x) Y(y) with obtain \frac{X''(x)}{X(x)} = \frac{Y''(y)}{Y(y)} = - \lambda
Now, be obtain two ordinary PDEs, X''(x) + \lambda X(x) = 0, and Y''(y) - \lambda Y(y) = 0.
I don't know how to continue from now one. Especially what to do with the non-homogeneous initial conditions.
Thank you very much in advance!
u_{xx} (x,y) + u_{yy} (x,y) = 0, with 0 < x < 2 \pi, 0 < y < 4 \pi
u_x (0,y) = 0, \, u_x(2 \pi, y) = 0, \, 0< y < 4 \pi
u(x,0) = a \cos(2x), \, u(x, 4 \pi) = a \cos^3(x), \, 0<x<2\pi
I think that the first step is to set u(x,y) = X(x) Y(y), from which the first equation becomes X''(x) Y(y) + X(x) Y''(y) = 0. And by dividing with X(x) Y(y) with obtain \frac{X''(x)}{X(x)} = \frac{Y''(y)}{Y(y)} = - \lambda
Now, be obtain two ordinary PDEs, X''(x) + \lambda X(x) = 0, and Y''(y) - \lambda Y(y) = 0.
I don't know how to continue from now one. Especially what to do with the non-homogeneous initial conditions.
Thank you very much in advance!