A Partial Differential - Thermodynamics

[Rdgmol]

Hello guys!
I'm new here, so sorry if I'm posting on wrong place or wrong way.

I just need help to solve a problem:
(∂E/∂V)β, N + β(∂p/∂β)N, V = - p

PS: There is a bar over E and over p (this in both sides) - meaning that is an average.

I don't know how to start, so any help will be amazing.
I'm not a physicist, so I'm having a bad time trying to solve this.

Thank you very much!

Equation latex
\left(\frac{\partial \overline{E}}{\partial V}\right)_{\beta, N} + \beta \left(\frac{\partial \overline{p}}{\partial \beta}\right)_{N, V} = - \overline{p}

 

[gleem]

Equation latex
\left(\frac{\partial \overline{E}}{\partial V}\right)_{\beta, N} + \beta \left(\frac{\partial \overline{p}}{\partial \beta}\right)_{N, V} = - \overline{p}

FYI in this forum

If you put your Latex code between double #'s you get your equation in line with the
text $\left(\frac{\partial \overline{E}}{\partial V}\right)_{\beta, N} + \beta \left(\frac{\partial \overline{p}}{\partial \beta}\right)_{N, V} = - \overline{p}$

if you put your Latex code between double $'s you get your equation alone and centered

$$\left(\frac{\partial \overline{E}}{\partial V}\right)_{\beta, N} + \beta \left(\frac{\partial \overline{p}}{\partial \beta}\right)_{N, V} = - \overline{p}$$