Partial differentiation question

VooDoo
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Hi guys,

I have the following question for a uni assignment, I have done part A and found the stationary points to be at

x=-2 x = 2
y=-1 y=1

Not sure if it is correct though.

I did this by using finding the partial derivatives using the quoitent rule, then making the partial derivatives equal to zero and solving for x and y. Now the second part of the question asks to find the second order DE, which would be an absolute pain to do using the quoitent rule. I am really, really lost guys. :cry:
 

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Whatever does the vertical line segment in the numerator signify??
 
arildno said:
Whatever does the vertical line segment in the numerator signify??
i think its a full stop that shouldn't be there
 
Thread 'Direction Fields and Isoclines'

Thread 'Direction Fields and Isoclines'

I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...
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