Particle Momentum and Position Calculation in Heisenberg Picture

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SUMMARY

This discussion focuses on calculating particle momentum and position using the Heisenberg picture in quantum mechanics. The key formula presented is \(\frac{dx}{dt} = \frac{p}{m}\), which relates the change in position over time to momentum. By knowing the position at two different times, \(x(t)\) and \(x(t+h)\), one can derive momentum using the expression \(x(t+\epsilon) - x(t) = \frac{p\epsilon}{m}\). The importance of distinguishing between differential equations involving operators and eigenvalues is emphasized to avoid confusion.

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eljose
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Let,s suppose we have a particle moving under a potential V:
By Heisenberg picture we know that:

\frac{dx}{dt}=p/m

so if we knew x(t) and x(t+h) we could calculate the expresion:

x(t+\epsilon)-x(t)=p\epsilon/m

so knowing x(t) and x(t+e) we could calculate the momentum of the particle:
 
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eljose said:
Let,s suppose we have a particle moving under a potential V:
By Heisenberg picture we know that:

\frac{dx}{dt}=p/m

so if we knew x(t) and x(t+h) we could calculate the expresion:

x(t+\epsilon)-x(t)=p\epsilon/m

so knowing x(t) and x(t+e) we could calculate the momentum of the particle:

Please do not mix the differential equation between operators and eigenvalues. They are completely different.


Seratend.
 

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