Particle motion in a Magnetic Field 1

[Gee Wiz]

Homework Statement

A charged particle of mass m = 6X10-8 kg, moving with constant velocity in the y-direction enters a region containing a constant magnetic field B = 2.8T aligned with the positive z-axis as shown. The particle enters the region at (x,y) = (0.58 m, 0) and leaves the region at (x,y) = 0, 0.58 m a time t = 884 μs after it entered the region.

What is Fx, the x-component of the force on the particle at a time t1 = 294.7 μs after it entered the region containing the magnetic field.

Homework Equations

F=qv*B (i realize it is the cross product, but since they are perpendicular i can just multiply them since the angle is 90)
M*a=F
a=(v^2)/R

The Attempt at a Solution

Well i think i can find the total Force by just doing m*(v^2)/R. I got that F=.109N
I assume this question has to with trig, but its not popping out to me how to attack it.

 

[Gee Wiz]

I've also tried to take the velocity times the time to me give distance.

 

[Gee Wiz]

Nevermind, figured it out.