Yes that is correct.fazal said:Homework Statement
A particle is moving along a straight trajectory. The distance covered by a particle is described by the function S(t)=2t^3+5t^2 , where t>0 is the time.
What is the distance covered by the particle by the time t=4
Homework Equations
The Attempt at a Solution
sub t=4 into the equation we get 2(4)^3+5(4)^2
=208 plse check fi this is correct??
A particle with variable velocity is a type of object that is constantly changing its speed as it moves. This can be due to factors such as acceleration or external forces acting on the particle.
The velocity of a particle with variable velocity can be calculated by taking the change in its position over a specific time interval. This is known as average velocity. Alternatively, the instantaneous velocity at a specific moment can be calculated by taking the derivative of the position function with respect to time.
Average velocity is the overall change in an object's position over a period of time, while instantaneous velocity is the velocity at a specific moment in time. Average velocity is calculated using the change in position over a specific time interval, while instantaneous velocity is calculated using the derivative of the position function.
The velocity of a particle with variable velocity affects its motion by determining how fast it is moving and in what direction. An increase in velocity will result in the particle moving faster, while a decrease in velocity will result in the particle moving slower. Changes in velocity can also cause changes in the particle's acceleration and position.
Yes, a particle with variable velocity can have a negative velocity. This means that the particle is moving in the opposite direction of its positive velocity. For example, if a particle is moving at a velocity of 10 m/s in the positive direction, a negative velocity of -10 m/s would mean that the particle is now moving in the negative direction at the same speed.