Particle with variable velocity

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SUMMARY

The distance covered by a particle moving along a straight trajectory is described by the function S(t) = 2t³ + 5t². By substituting t = 4 into the equation, the calculation yields S(4) = 2(4)³ + 5(4)² = 208. This confirms that the distance covered by the particle at t = 4 is indeed 208 units. The solution has been verified as correct by other participants in the discussion.

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fazal
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Homework Statement



A particle is moving along a straight trajectory. The distance covered by a particle is described by the function S(t)=2t^3+5t^2 , where t>0 is the time.

What is the distance covered by the particle by the time t=4


Homework Equations





The Attempt at a Solution



sub t=4 into the equation we get 2(4)^3+5(4)^2
=208 plse check fi this is correct??
 
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fazal said:

Homework Statement



A particle is moving along a straight trajectory. The distance covered by a particle is described by the function S(t)=2t^3+5t^2 , where t>0 is the time.

What is the distance covered by the particle by the time t=4


Homework Equations





The Attempt at a Solution



sub t=4 into the equation we get 2(4)^3+5(4)^2
=208 plse check fi this is correct??
Yes that is correct.
 

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