Partition function for one particle

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The energy distribution of a single particle can indeed follow the Boltzmann distribution when it is in contact with a heat bath at a fixed temperature. The partition function can be used to derive the probability distribution for the particle's energy, expressed as P(E) = exp(-E/T)/Z. However, a single particle alone does not possess a well-defined temperature. The interaction with the heat bath allows the particle to exhibit behavior consistent with thermodynamic principles. Thus, the Boltzmann distribution applies under these specific conditions.
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Does the energy distribution of one particle also follow the Boltzmann distribution. I.e. can you get the energy distribution for a single particle by calculating its partition function and writing:
P(E) = exp(-E/T)/Z
 
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A single particle does not have a well-defined temperature.
If that single particle is in contact to some "container" (heat bath) with a fixed temperature, it will follow the Boltzmann distribution.
 

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