Password Combinations: 2 Alphabetic + 3 Digits

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The discussion centers on calculating the number of unique passwords composed of 2 alphabetic letters and 3 digits from the set {3, 4, 5, 6, 7}, with no repetitions allowed. Participants debate whether the problem requires a combination or permutation approach, highlighting ambiguity in the order of letters and digits. One user suggests that the total can be calculated by multiplying the choices for each character, arriving at an answer of 39,000, though this is contested. Clarifications about the interpretation of the problem emphasize the importance of specifying whether letters and digits can be in any order. The conversation concludes with acknowledgment of the need for clearer problem statements to avoid confusion.
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Homework Statement


Passwords are made up of 2 alphabetic letters and 3 digits from the digits 3,4,5,6,7. How many passwords are there with no letter or digit being repeated?


Homework Equations



im confused as to whether its a combination or a premutation

The Attempt at a Solution


didnt have a clue how to do this
 
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How many ways are there to chose the first letter/digit of the password?

After that choice is made, how many ways are there to choose the second letter/digit?

Etc.

(I'm assuming that the letters and digits can appear in any order; the problem could be read as saying that a password is 2 letters followed by 3 digits.)
 
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Whats best to solve stats problems is to think about the problems logically. Formulas sometimes lead you astray. Also, as Avodyne stated the question is ambiguously worded. Can the numbers & letters be in any order, or is it specifically 2 letters then 3 numbers?

If there is no specific order, slot one will have 26+5 possible choices. Then if the letter or number can't be repeated... how many choices will you have for the second slot?

31*second slot*third slot...*fifth slot
 
i got the answer! you just simply multiply these number 26 . 25. 5.4.3 =39000
 
tramtran111 said:
i got the answer! you just simply multiply these number 26 . 25. 5.4.3 =39000

Its best not to solve the problems for people, but rather to give them hints & allow them to solve the problem.
 
Avodyne said:
(I'm assuming that the letters and digits can appear in any order; the problem could be read as saying that a password is 2 letters followed by 3 digits.)

Your two sentences above contradict each other. Why should the problem could be read as you say? Any letter or number can sit anywhere, which you said in the first sentence.

tramtran111 said:
i got the answer! you just simply multiply these number 26 . 25. 5.4.3 =39000

You answer is wrong.

fionadlegend said:
Passwords are made up of 2 alphabetic letters and 3 digits from the digits 3,4,5,6,7. How many passwords are there with no letter or digit being repeated?

Homework Equations



im confused as to whether its a combination or a premutation
A bit of both.

Select any two alphabets, which can be done in 26C2 ways.
Select any three numbers now out of the five given in the same way.

All these cases are mutually exclusive and exhaustive. So, now just permute the five different symbols.

Waiting for your answer.
 
Avodyne said:
(I'm assuming that the letters and digits can appear in any order; the problem could be read as saying that a password is 2 letters followed by 3 digits.)

Shooting Star said:
Your two sentences above contradict each other. Why should the problem could be read as you say? Any letter or number can sit anywhere, which you said in the first sentence.

I believe it would be clearer if he had included a word "but"

"I'm assuming that the letters and digits can appear in any order; but the problem could be read as saying that a password is 2 letters followed by 3 digits."
 
HallsofIvy said:
I believe it would be clearer if he had included a word "but"

"I'm assuming that the letters and digits can appear in any order; but the problem could be read as saying that a password is 2 letters followed by 3 digits."

Well, if I had faced this problem in an exam, in the form the OP has given it, I would have interpreted it as the letters and numbers occurring in any position, which is Avodyne's first interpretation. Nowhere it is implied that the first two are alphabets.

But yes, with a "but" in Avodyne's second statement, it would remove the contradiction with his first assertion.
 
I agree with you. But posters here don't always copy the problem correctly and having "alphabet first, then digits" is common enough that it would be reasonable to at least note it.
 
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HallsofIvy said:
I agree with you. But posters here don't always copy the problem correctly and having "alphabet first, then digits" is common enough that it would be reasonable to at least note it.

That is a good thing you have pointed out. I hadn't taken into consideration the youth of the posters here. I'll keep it in mind. Thanks, HallsofIvy.
 

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