PE/KE-Bullet Hits a Hanging Block?

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The discussion revolves around calculating the kinetic energy (KE) of a bullet before it strikes a hanging block and the maximum potential energy (PE) of the block after being hit. The bullet, weighing 0.05 kg, causes a 4 kg block to swing upwards by 0.50 m, leading to the use of the equations PE = mgh and KE = 1/2 mv^2. Participants suggest using conservation of momentum to determine the bullet's speed, noting that some energy will be lost to deformation and heating rather than fully converting to gravitational potential energy. It is also mentioned that while momentum is conserved horizontally, vertical momentum conservation is affected by gravity. The conversation emphasizes the need for careful consideration of energy transformations in this scenario.
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PE/KE--Bullet Hits a Hanging Block?

Homework Statement


A .05 kg bullet hits a 4 kg block hanging 1.5 m from the ceiling, displacing it by a height of .50 m. What is the KE of the bullet before it hits the block, and what is the max PE of the block?
(So basically, a bullet hits a hanging block and makes it swing upwards by .50 m)

Homework Equations


PE = mgh
KE = 1/2 mv^2


The Attempt at a Solution



I wanted to use 1/2 mv^2 to find the KE of the bullet before hitting the box, but where would I get v from? I figured I could set something equal to the max PE of the block which I'm assuming is 4 (9.8) (.50), but how would I find v?
I figured the max PE of the block would just be mgh, so: 4 (9.8) (.50) But somehow that felt too easy, and I thought there should be more too it?
 
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Merlinnair said:

Homework Statement


A .05 kg bullet hits a 4 kg block hanging 1.5 m from the ceiling, displacing it by a height of .50 m. What is the KE of the bullet before it hits the block, and what is the max PE of the block?
(So basically, a bullet hits a hanging block and makes it swing upwards by .50 m)

Homework Equations


PE = mgh
KE = 1/2 mv^2


The Attempt at a Solution



I wanted to use 1/2 mv^2 to find the KE of the bullet before hitting the box, but where would I get v from? I figured I could set something equal to the max PE of the block which I'm assuming is 4 (9.8) (.50), but how would I find v?
I figured the max PE of the block would just be mgh, so: 4 (9.8) (.50) But somehow that felt too easy, and I thought there should be more too it?

Using conservation of momentum is the only way to find the speed of the bullet.
 


A lot of the KE of the bullet will be used for deformation and heating of the block. So only a small amount of the KE of the bullet will be turned into the GPE of the block.

On the other hand, momentum is conserved. So you could use a momentum calculation to find out what the speed of the bullet was.

Edit: of course, momentum isn't conserved in the vertical direction, since we probably want to model the gravitational field as approximately constant. You could shoot the block horizontally and measure how far it swings out to? The momentum of the bullet would be transferred to the block as if the block were a pendulum.
 
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