Pendulum Formulas Homework: Newton's law & s'' in terms of theta

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Homework Help Overview

The discussion revolves around deriving formulas related to a pendulum, specifically Newton's law in terms of acceleration, angle, and gravitational force. Participants are exploring the relationship between arc length and angle in the context of pendulum motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to express Newton's law using variables related to the pendulum's motion but struggles to combine them into a single formula. They also seek to define acceleration in terms of angular acceleration.
  • Some participants question how arc length relates to the pendulum's length and angle, with one participant providing a derivation involving small angle approximations and integration.
  • Others express confusion about the integration process and its relevance to the current curriculum.

Discussion Status

The discussion is ongoing, with participants sharing insights and derivations. Some guidance has been offered regarding the relationship between arc length and angle, but there is no explicit consensus on the understanding of integration or its application in this context.

Contextual Notes

Participants note that integration has not been covered in their calculus course, which may be impacting their understanding of the derivations being discussed.

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Homework Statement


1. write Newton's law in terms of s'' theta and g for a pendulum
2. define s'' in terms of theta''

Homework Equations





The Attempt at a Solution



1.
G = -mgsin theta

and G = m s''


but i can't get all three of the required variables into one formula




2.
s'' = -g sin theta

i can't get to theta'' i thought about doing intergrals but i can't figure it out
 
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If the pendulum has length l and makes an arc of angle θ, how is the arc length s, related to both l and θ?
 
for an angle of 2pi (measured in rads), you have arc length 2pi*l, for an angle of theta it is theta*l. Detailed proof of this might need integrals to calculate the arc length or to prove it geometrically: for very small theta d\theta the arc length ds would be equal to the string length dr and equal to 2lsin(d\theta/2). But because d\theta is small sin(d\theta/2)=d\theta/2. So ds=ld\theta and thus by simple integration s=l\theta.
 
i don't get it still ;;
 
sporus said:
i don't get it still ;;

Delta2 shows you the derivation to arrive at the relation of s=lθ.
 
does that mean that what he posted above was integration? i didn't get that because we haven't covered that in calc yet. i'll go over it again and try to get it
 
sporus said:
does that mean that what he posted above was integration? i didn't get that because we haven't covered that in calc yet. i'll go over it again and try to get it

It essentially becomes the same as finding the arc length given the radius l and and angle θ.
 

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