Solving Percentage Questions: 231 mg Potassium in Dandelions vs 93 mg in Lettuce

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To determine the percentage difference in potassium content between dandelions and lettuce, one must first calculate the absolute difference in potassium levels, which is 231 mg - 93 mg = 138 mg. The percentage increase can then be calculated using the formula (difference/amount in lettuce) * 100, resulting in approximately 148.39% more potassium in dandelions compared to lettuce. Alternatively, using the dandelion's potassium content as the reference, the calculation yields about 59.74% more potassium in dandelions relative to their own amount. It's crucial to clarify the reference point when discussing percentage differences, as it can lead to varying interpretations. Accurate comparisons require similar serving sizes for both dandelions and lettuce to ensure relevance.
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Homework Statement


So I'm drawing a complete blank on how to figure out some easy math...like given that there is 231 mg of potassium in a dandelion and 93 mg of potassium in lettuce, how much more (%wise) is there of potassium in dandelions...

Homework Equations


The Attempt at a Solution


i thought at first that its (93/231)*100= 40.26% but then i started second guessing myself...
 
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(1) How much more is there in dandelion than in lettuce?
Answer: (amount in dandelion) - (amount in lettuce)
(2) What percentage is this of the amount of potassium in ...
 
gerben said:
(1) How much more is there in dandelion than in lettuce?
Answer: (amount in dandelion) - (amount in lettuce)
(2) What percentage is this of the amount of potassium in ...

sorry but i don't quite get what you said for (2)...
 
final-initial/initial = percent gain
 
I left the... to make clear you still had to decide whether you want to know either A or B:

A: (how much more (%wise) is there of potassium in dandelions than in lettuce) relative to the amount in lettuce.

B: (how much more (%wise) is there of potassium in dandelions than in lettuce) relative to the amount in dandelion.
 
gerben said:
I left the... to make clear you still had to decide whether you want to know either A or B:

A: (how much more (%wise) is there of potassium in dandelions than in lettuce) relative to the amount in lettuce.

B: (how much more (%wise) is there of potassium in dandelions than in lettuce) relative to the amount in dandelion.

like for some reason, I'm still kind of confused...like this is what I've got...
(231-93)/93 = 148.39% more potassium in dandelions
Is this right or should it be the opposite way meaning (231-93)/231= 59.74% more potassium in dandelions...?
 
Yes, there is "(231-93)/93 = 148.39% more potassium in dandelions" then in lettuce, relative to the amount in lettuce (that is: the amount more in dandelion than in lettuce is equal to 148.39% of the amount in lettuce)

When they ask "%-wise" it is not always clear what is meant, a percentage is always relative to something. Another correct answer would be:

There is (231-93)/231 = 59.74% more potassium in dandelions then in lettuce, relative to the amount in dandelions (that is: the amount more in dandelion than in lettuce is equal to 59.74% of the amount in dandelion)
 
lha08 said:
So I'm drawing a complete blank on how to figure out some easy math...like given that there is 231 mg of potassium in a dandelion and 93 mg of potassium in lettuce, how much more (%wise) is there of potassium in dandelions...
In a way, you're comparing apples to oranges here. The only way you can compare percentages of potassium in dandelions and lettuce is to compare quantities that are comparable. You say there are 231 mg of potassium (K) in a dandelion. How big a serving of lettuce contains the 93 mg of K? Unless otherwise stated you should be comparing one dandelion with an amount of lettuce of about the same weight.
 
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