# Permutations form subgroup.

## Homework Statement

Consider the group D4 (rigid motions of a square) as a subgroup of S4 by using
permutations of vertices. Identify all the even permutations and show that they form a subgroup of D4.

## The Attempt at a Solution

I think I have the permutations of correct. They are: (1,2,3,4), (1,3)(2,4), (1,4,3,2), (1), (2,4), (1,3), (1,2)(3,4), (1,4)(2,3). If this is correct, then the only one that is not even is (1).

Can someone check my work thus far? I know how to go about proving it is a subgroup assuming the rest is correct.

Related Calculus and Beyond Homework Help News on Phys.org
Dick
Homework Helper
Your list of group elements looks correct. The conclusion that (1) is not even is dead wrong. Better reread the definition of an 'even' permutation. There are four even permutations in there and four odd ones.

The four even then would be (13)(24), (12)(34), (14)(23), and (1), correct?

Is 1 even because it is 0 transpositions?

Dick
Homework Helper
The four even then would be (13)(24), (12)(34), (14)(23), and (1), correct?

Is 1 even because it is 0 transpositions?
Yes.

Dick
Homework Helper
The four even then would be (13)(24), (12)(34), (14)(23), and (1), correct?

Is 1 even because it is 0 transpositions?
Yes.

I'm having some problems completing the proof that the set of even elements forms a group under D4. I do know that if G is any group of permutations then the set of all even permutations G form a subgroup of G, but I'm not sure how to prove that. Does that seem the like the easiest way to go about it?

Dick