Peukerts Law Based on Manufacturer Information

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The discussion centers on deriving Peukert's exponent for batteries, particularly in relation to assumptions about discharge time and current. The original poster struggles with the mathematical approach to find the exponent, questioning why their calculations yield zero. Participants clarify that using manufacturer-rated values without accounting for actual performance can lead to misleading results, as Peukert's law primarily applies to lead-acid batteries and may not be suitable for lithium-ion types like LiFePO4. They emphasize that factors such as temperature and discharge profiles significantly influence battery performance, suggesting that experimental data is necessary for accurate calculations. Overall, the conversation highlights the complexities of battery behavior and the limitations of applying Peukert's law across different battery chemistries.
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So I have been trying to derive peukerts exponent based on assumptions I know this won't be accurate but I am curious about the data. So I don't know the time to discharge the battery so I guessed 3 Hours the capacity at a 20 hour rate is 40Ah meaning the manufacturer rated discharge current was 2A. However I ran into an issue with this because I get log(3)=log((40/(2*20))^k) then when I take log base 2 of 1 I get 0. Mathematically I see this but I am not sure why trying to find for k this way won't work. I know assuming some random discharge time makes no sense but let's say experimentally I found that to be 3 when using a discharge current of 2A then could I use the equation in this way? I still could not because I would still get a 0 on the other side. So I guess my question actually is why can't I use this equation in the manner I am trying? It must be because they are inherrrent losses in the battery and so the capacity listed in the numerator won't be exactly as rated.
 
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DodgeViperEvilTwin said:
So I have been trying to derive peukerts exponent based on assumptions I know this won't be accurate but I am curious about the data.

I'm confused by your question. Are you trying to derive it based soley on a curve fit where the single input is discharge time?

I'm not sure if you'll get a better answer here or in the Chemistry forum. If no good answers appear, I'll try moving this thread to chemistry.

Lead-acid batteries are complicated. Thinking "I put energy in, so I'll get energy out (minus some percent loss)" is far too simplified.

Have you read https://en.wikipedia.org/wiki/Peukert's_law ?
Also this http://www.smartgauge.co.uk/peukert_depth.html
 
anorlunda said:
I'm confused by your question. Are you trying to derive it based soley on a curve fit where the single input is discharge time?

I'm not sure if you'll get a better answer here or in the Chemistry forum. If no good answers appear, I'll try moving this thread to chemistry.

Lead-acid batteries are complicated. Thinking "I put energy in, so I'll get energy out (minus some percent loss)" is far too simplified.

Have you read https://en.wikipedia.org/wiki/Peukert's_law ?
Also this http://www.smartgauge.co.uk/peukert_depth.html
I just mean based on the equation on the Wikipedia page you linked how can I find k if I know t, H,C, and I? This is for a LiFePO4 based battery not that it matters but I wanted an exact number I didn't just want to pull typical numbers that's why I am trying to figure this out I am hoping with this number I can somehow arrive at an approximate number for reserve capacity
 
If I've understood correctly...

The formula uses the rated capacity and (indirectly) the actual capacity from I and t.

If you feed it data that implies these are the same then I believe you will indeed get k=0 because anything to the power 0 is equal to 1.

I think K=0 implies an ideal battery where the capacity doesn't change with current draw.

Sorry if I have this wrong but I'm getting interrupted.
 
DodgeViperEvilTwin said:
I just mean based on the equation on the Wikipedia page you linked how can I find k if I know t, H,C, and I? This is for a LiFePO4 based battery not that it matters but I wanted an exact number I didn't just want to pull typical numbers that's why I am trying to figure this out I am hoping with this number I can somehow arrive at an approximate number for reserve capacity
I ordered an electronic load tester so that way I can draw a constant 10A and read the capacity at that draw. Which if I time the point at which I fully drain the battery then I can find k.
 
CWatters said:
If I've understood correctly...

The formula uses the rated capacity and (indirectly) the actual capacity from I and t.

If you feed it data that implies these are the same then I believe you will indeed get k=0 because anything to the power 0 is equal to 1.

I think K=0 implies an ideal battery where the capacity doesn't change with current draw.

Sorry if I have this wrong but I'm getting interrupted.
I think I understand where the issue comes from I am trying to use the manufacturers rated current not necessarily the load they applied. Therefore I don't have the actual number that the equation called for.
 
The second link I provided says that the coefficient must come from the manufacturer. Presumably, you could do the experiments yourself, but it might be a lot of work.

What is the value of an exact number for k? There are a number of other factors including temperature, and sulphation of the plates, and current-versus-time-profile that significantly change performance more significantly than small changes in k.
 
anorlunda said:
The second link I provided says that the coefficient must come from the manufacturer. Presumably, you could do the experiments yourself, but it might be a lot of work.

What is the value of an exact number for k? There are a number of other factors including temperature, and sulphation of the plates, and current-versus-time-profile that significantly change performance more significantly than small changes in k.
I was hoping to get it so I could play with some calculations to determine if this battery holds an advantage of its lead acid counterparts in terms of capacity.
 
I'm not sure that LiFePO4 even follow the same shaped curve.
 
  • #10
anorlunda said:
The second link I provided says that the coefficient must come from the manufacturer. Presumably, you could do the experiments yourself, but it might be a lot of work.

What is the value of an exact number for k? There are a number of other factors including temperature, and sulphation of the plates, and current-versus-time-profile that significantly change performance more significantly than small changes in k.
I see batteries in the same group size but they indicate higher Ah rating yet I always thought LiFePO4 batteries were better. So I was curious to find the true k value so I could do a proper comparison. I have the reserve capacity of the other but it is unlisted for the battery I am messing with and the manufacturer does not know.
 
  • #11
anorlunda said:
I'm not sure that LiFePO4 even follow the same shaped curve.
I am still learning about all of this they may well not however I assumed they might be close as they have somewhat similar cell voltages when at 12V. So they have 12.8 nominal and the lead acid has 12.6V I know that is trivial but I am thinking they would then have similar charge profiles as the top voltage on lead acid is 14.4V and 14.6V for LiFePO4.
 
  • #12
The Wikipedia article says
Peukert's law was developed for Lead-Acid batteries, and works well in that application.

It does not necessarily apply to other battery chemistries, especially Lithium-Ion batteries. Lithium-Ion batteries tend to self-heat during rapid discharge, and the Nernst Equation predicts battery voltage will increase with temperature. Thus, the effect of increased resistance is offset by the self-heating effect. This advantage of Lithium-Ion batteries is a well-known advertised feature, see [1]. In a research paper, a 50Ah lithium-ion battery tested was found to give about the same capacity at 5A and 50A; this was attributed to possible Peukert loss in capacity being countered by the increase in capacity due to the 30◦C temperature rise due to self-heating, with the conclusion that the Peukert equation is not applicable.[3]
 
  • #13
anorlunda said:
The Wikipedia article says
Well that answers that then I did not even see that.
 
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