PH concentrations, strong acids and water

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The discussion centers on calculating the pH of a 0.05 mol/dm³ HCl solution and whether to consider the contributions of [H+] and [OH-] from water. It is clarified that in such dilute solutions, the acid completely dissociates, and the concentration of water can be treated as neutral, meaning its contributions can often be ignored for pH calculations. When the concentration of the acid is above 5 x 10^-7 M, the additional [H+] from water is negligible. The participants express gratitude for the clarification and acknowledge their understanding of pH calculations. Overall, the focus is on accurately determining pH in the context of strong acids in aqueous solutions.
nobahar
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Hello!
I was wondering, with questions such as "What is the pH of 0.05 mol dm-3 of HCl?", you specify the pH by simply using the concentration, as it completely dissociates. However, I assume that at such a concentration like this it is not 'pure', and would be present in water. Shouldn't I then have to consider the [H+] and [OH-] concentrations of water?
Thanks for any help.
 
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They are in water, that's what mol/dm3 means.
So in every liter of solution, there is 0.05 mol of HCl. The rest is pure water, which is neutral (in the sense that the concentration of H+ and OH- is equal to great accuracy).
 
so shouldn't the [H+] introduced be included with the [H+] of the water for an overall pH value?
Sorry, it has not been a good day...
 
nobahar said:
so shouldn't the [H+] introduced be included with the [H+] of the water for an overall pH value?

If concentration of acid is high enough they can be safely ignored. High enough in this context means more than 5*10-7M.

See calculation of pH of strong acid for more details.
 
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