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how do u calculate the pH of a solution of CaCO3(s) in 1.0 M NH4Cl?
Impossiblebt said:For material balance, carbonate-containing species: 1.0 = [CO32-] + [HCO3-]
Impossiblebt said:I suppose it shouldn't be equal to one... do we not know what it should be equal to?
As asked, the equations that describes the system are as follows:
CaCO3 ---> Ca2+ + CO32-
H2CO3 + H2O ---> H3O+ + HCO3-
HCO3- + H2O ---> H3O+ + CO32-
H2O ---> H3O+ + OH-
NH4+ + H2O ---> H3O+ + NH3
Would it be ok to state that [CO32-] + [HCO3-] is equal to [H30+] - [NH3]? I derived that from looking at the reactions that occur in the system. I don't know if this conclusion helps me at all in finding the answer, but the statement does contain [H3O+ which is what I'm looking for.Borek said:Sure. Think where do the carbonates come from. What othe rions is produced in teh same process?
Well we don't care about water, and the only quantity we know for sure is NH4+ being 1mol / 1M.Borek said:That's will give five equations (assuming we know all equilibrium constants). How many unknowns? What other equations do you have?
Impossiblebt said:Would it be ok to state that [CO32-] + [HCO3-] is equal to [H30+] - [NH3]?
Are any of the [H3O+] quantities in our reactions the same or are they all different? I don't know how many unknowns we have until I know the answer to that.
chemchem said:what do the H+ ions do to the CO3 in the CaCO3?