Phase Transitions: Why is the pressure constant?

Click For Summary
SUMMARY

The discussion centers on the behavior of pressure during phase transitions, specifically the assumption that dP=0, which allows the equation dH=TdS to hold true. Participants clarify that during a phase change, the pressure of the system aligns with the ambient atmospheric pressure. When phase changes occur in non-constant pressure environments, the integral term ∫VdP must be considered, leading to the equation ΔH = ∫dH = ∫TdS + ∫VdP. This highlights the importance of understanding the thermodynamic principles governing phase transitions.

PREREQUISITES
  • Understanding of thermodynamics and phase transitions
  • Familiarity with the concepts of enthalpy (H) and entropy (S)
  • Knowledge of the ideal gas law and its implications in phase changes
  • Basic grasp of calculus, particularly integrals in thermodynamic equations
NEXT STEPS
  • Study the implications of the Clausius-Clapeyron equation in phase transitions
  • Learn about the Gibbs phase rule and its applications
  • Explore the concept of latent heat and its role in phase changes
  • Investigate the effects of varying pressure on phase diagrams
USEFUL FOR

Students and professionals in physics, particularly those focusing on thermodynamics, as well as researchers interested in material science and phase behavior under varying environmental conditions.

madshiver
Messages
8
Reaction score
0
I have a question regarding phase transitions:

It all textbook I've seen the assumption that dP=0 during a phase transition (so that for example dH=TdS is true during a phase transition). Could anyone explain why this should be true?

I guess I could relate this question to a question I had during intro (Halliday) Physics: Why can we assume that temperature is constant during a phase transition? (Back then I imagined that after a certain point putting in energy to get the molecules to move faster does not really lead to a substantial increase in entropy, so that the rigid structure e.g. of the solid or the liquid has to be broken down, so that subsequent temperature increase would actually lead to a decent entropy increase, at the cost of reduced internal energy.)

And then the final related question: Why can't the pressure and temperature both change by "wandering" along the phase-transition line?
 
Physics news on Phys.org
madshiver said:
I have a question regarding phase transitions:

It all textbook I've seen the assumption that dP=0 during a phase transition (so that for example dH=TdS is true during a phase transition). Could anyone explain why this should be true?
For a phase change in the open atmosphere, the pressure of the system is always equal to the ambient pressure of the surroundings ie the atmosphere. If the phase change takes place in an environment in which pressure is not constant, you would have to take the ∫VdP term into account. In such a case ΔH = ∫dH = ∫TdS + ∫VdP

AM
 
Thanks :).
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
12K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 1 ·
Replies
1
Views
491